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Amiraneli [1.4K]
3 years ago
5

3

Mathematics
1 answer:
saveliy_v [14]3 years ago
7 0

Answer:

sorry you can send me picture of work

Step-by-step explanation:

ok send me and get answers

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-<br> Use the order of operations to simplify 4(3.5 - 1.5) -
irinina [24]

Answer:

When simplified this equation equals 8.

Step-by-step explanation:

Let me show you my work.  

4 ( 3.5 - 1.5 ) = 4 ( 2 )

4 ( 2 ) = 8 because 4 times 2 = 8

Hope this helps. . .

UwU

6 0
2 years ago
Read 2 more answers
What is the mean median mode and range of the numbers 31 28 30 31 30 ...?
mamaluj [8]
1. Mean is the number you get when you add all these numbers and then divide by the number of numbers. So, (31 + 28 + 30 + 31 + 30) / 5 = 150 / 5 = 30
2. The median is the middle number in the list of numbers, so, the answer is 30 as well.
3. Mode is the number that appears most often, so here it is 30 and 31 because they both appear 2 times.
4. Range is the difference between the largest and smallest number, so 31 - 28 = 3. 
5 0
3 years ago
2x + 3 = 4x^2<br> completing the square
ch4aika [34]

Answer:

\frac{1+\sqrt{13} }{4}, \frac{1-\sqrt{13} }{4}

Step-by-step explanation:

First, make them on one side of the formula in the form of ax^2+bx+c=0 which is 4x^{2} -2x-3=0

Next, insert the corresponding number in the quadratic formula, \frac{-b+\sqrt{b^{2}-4ac } }{2a}  ,\frac{-b-\sqrt{b^{2}-4ac } }{2a} , and the answer can be calculated.

6 0
2 years ago
Find the equation of the exponential function represented by the table below:​
aivan3 [116]

Answer:

I believe its y=5(4)^x

Step-by-step explanation:

The equation is supposed to look like y=ab^x

a is basically where it all starts, so where the y meets the 0

- so the 5 in the y's place meets the 0

b is what you're multiplying by on the y's side, which is by 4 every time

and the x is the exponent and since there is no exponent you leave it as x

4 0
3 years ago
Can someone help me with this question
jonny [76]
67/100 is approximately 2/3 and 515 is approximately 510 so D. 2/3*510
6 0
3 years ago
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