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3 years ago

If anyone can help me I’ll give all my points to u..

Mathematics

2 answers:

V125BC [204]3 years ago

7 0

Answer:

${x}^{2} + 6x - 8 - 3x + 2 - 3 {x}^{2} \\ = (1 - 3) {x}^{2} + (6 - 3)x + 2 - 8 \\ = - 2 {x}^{2} + 3x - 6$

4x+4+2x+2-8x

=(4+2-8)x +4+2

=-2x+6

balu736 [363]3 years ago

5 0

Answer: 12x squared

Step-by-step explanation:

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I need the answer asap!!!! thanks!

vova2212 [387]

Y=-7/2x+1/2

i already typed the work out but something went wrong?
1. find slope
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3 years ago

How many additional cups of sugar are needed?

storchak [24]

Answer:

Step-by-step explanation:

since $p =s$ , and $p=6$ ,

$s=6$ .

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3 years ago

Jenna live 4 3/10 miles from school. She estimates that she travels 4x2x5,or 40 miles each week.Is her estimate an overestimate

umka21 [38]

Hey

Jenna lives 4 3/10 miles from school, she estimates that she travels 4 x2x5 or 40 miles each week. Is her estimate an over estimate or underestimate? I think it is under estimate but not sure?

Hoped I Helped

7 0

3 years ago

Read 2 more answers

HELP ME PLEASEEEEEEEEEEEEEEE

frutty [35]

The answer is: 98

Cause is you add everything you will get that

3 0

3 years ago

Read 2 more answers

I am extremely confused, can anyone help?

JulijaS [17]

Answer:

So I did most of you table for you:

First blank:4

Second blank:-4

Third blank:-8

Fourth blank: Left to you: Just plug in 6 into 1/2x^2-5x+4 (I will check)

Fifth blank: Left to you: Just plug in 8 into 1/2x^2-5x+4 (I will check)

The graph is D.

Step-by-step explanation:

So they have a table to fill in and they tell you in the first row what they want you to plug in

So the table is asking us to answer this:

What is h(0),h(2),h(4),h(6), and h(8).

h(0) means to replace x with 0 in $\frac{1}{2} x^2-5x+4$ .

$\frac{1}{2}(0)^2-5(0)+4$

$0-0+4$

$0+4$

$4$

So the first blank is 4 since h(0)=4.

h(2) means to replace x with 2 in $\frac{1}{2} x^2-5x+4$ .

$\frac{1}{2} (2)^2-5(2)+4$

$\frac{1}{2} (4)-10+4$

$2-10+4$

$-8+4$

$-4$

So the second blank is -4 since h(2)=-4.

h(4) means to replace x with 4 in $\frac{1}{2} x^2-5x+4$ .

$\frac{1}{2}(4)^2-5(4)+4$

$\frac{1}{2}(16)-20+4$

$8-20+4$

$-12+4$

$-8$

So the third blank is -8 since h(4)=-8

Maybe you can try the last 2 blanks in the table part. That is try computing h(6) and h(8). I will check it for you.

Now the points I have so far are (0,4) from the h(0)=4, (2,-4) from the h(2)=-4, and (4,-8) from the h(4)=-8.

I'm looking for a graph that goes through these points (0,4) , (2,-4) , and (4,-8).

By the way the only graphs that are worth looking at is C and D because they are open up. I know my curve for h(x)=1/2x^2-5x+4 should be a parabola open up because 1/2 is positive and 1/2 is the coefficient of x^2.

So Graph C has y-intercept (0,10) not (0,4) so Graph C is not right.

Graph D has y-intercept (0,4). It also goes through (2,-4) and (4,-8).

I don't know if you notice but the x-axis and y-axis are going up by two's in each graph.

7 0

3 years ago