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boyakko [2]
3 years ago
5

Please help me by answering this?

Mathematics
1 answer:
Dmitrij [34]3 years ago
8 0

Answer:

180

Step-by-step explanation:

\frac{6}{2} x^{2} | \frac{8}{2}

192-12=180

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Five cakes cost 4.00 how much do 7 cost
Bond [772]
You need to divide 5/4 and youll get the price for 1 cake (1.25) then just add 2 more times to 5 (6.5) is the total
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3 years ago
Read 2 more answers
-0.7y = 9.1<br> Please help explain as well
Fittoniya [83]
Hope this helps
Answer: y= -13

3 0
3 years ago
A positive number is 3 times another number.
Juli2301 [7.4K]

Answer:

The smaller number can be 8 or \frac{1}{5}.

Step-by-step explanation:

Consider the provided information.

let the larger number is x and the smaller number is y

A positive number is 3 times another number.

3y=x

If we add 2 to the larger and 5 to the smaller, then one of them becomes 2 times the other.

Case I: If 2nd number is 2 times to the first number.

x+2=2(y+5)

Substitute the value of x.

3y+2=2y+10

y=8

Now substitute the value of y in 3y=x

3(8)=x

x=24

Therefore, the smaller number is 8.

Case II: If 1st number is 2 times to the second number.

2(x+2)=y+5

Substitute the value of x.

2(3y+2)=y+5

6y+4=y+5

5y=1

y=\frac{1}{5}

Therefore, the smaller number is \frac{1}{5}.

7 0
4 years ago
A ranger stands at the top of a 160-foot tower. He spots a campfire at an 8° angle of depression.
Montano1993 [528]
See the attached picture for the solution:

 May need to round to 23 feet.

3 0
3 years ago
The height of a small rock falling from the top of a 124-ft-tall building with an initial downward velocity of –30 ft/sec is mod
Contact [7]

Answer:

Option 3.

Step-by-step explanation:

The given function is

h(t)=-16t^2-30t+124

where, h(t) is the height of a small rock falling from the top of a 124-ft-tall building and t is the time in seconds.

It is a downward parabola.

Equate the function equal to 0, to find the time at which the rock touch the ground.

-16t^2-30t+124=0

If ax^2+bx+c=0, the according to the quadratic formula

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

Using quadratic formula, we get

t=\dfrac{-(-30)\pm \sqrt{(-30)^2-4(124)(-16)}}{2(-16)}

t=\dfrac{30+\sqrt{(-30)^2-4(124)(-16)}}{2(-16)},\dfrac{30-\sqrt{(-30)^2-4(124)(-16)}}{2(-16)}

t=-3.875, 2

Time cannot be negative. So, the rock remain in the air in the interval 0 < t < 2.

Therefore, the correct option is 3.

6 0
3 years ago
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