Answer:
5 = 6q - 30 - 19
5 = 6q - 49
54 = 6q
9 = q
Step-by-step explanation:
Step-by-step explanation:
2x + 7 = 27 OR 3 + 3x = 30.
2x = 27 - 7 OR 3x = 30 - 3
2x = 20 OR 3x = 27
x = 20/2 OR x = 27/3
x = 10 OR x = 9
Formula used: 40+x = 4x-3 x is used for <em>ET</em>
Step-by-step explanation:
40+x = 4x-3
<u>+</u><u>3</u> <u>+</u><u>3</u>
43+x = 4x
<u>-</u><u>x</u> <u>-</u><u>x</u>
<u>43</u> = <u>3x</u>
3 3
14.3 = x
then substitude this on 5x+3 on <em>W</em><em>T</em> and you arr good
Since you know the value of "x", you can plug in the value for "x" in the equation.
[When an exponent is negative, you move it to the other side of the fraction to make the exponent positive.]
For example:
or 
or y³
x = -2
f(x) = 9x + 7
f(-2) = 9(-2) + 7 = -18 + 7 = -11

(idk if you should have it as a decimal or a fraction)
x = -1
f(x) = 9x + 7
f(-1) = 9(-1) + 7 = -9 + 7 = -2


x = 0
f(x) = 9x + 7
f(0) = 9(0) + 7 = 7


x = 1
f(x) = 9x + 7
f(1) = 9(1) + 7 = 9 + 7 = 16


x = 2
f(x) = 9x + 7
f(2) = 9(2) + 7 = 18 + 7 = 25


You need to determine the solution of f(x) = g(x)
Since you know f(x) = 9x + 7 and
, you can plug in (9x + 7) for f(x), and (
) into g(x)
f(x) = g(x)
You can plug in each value of x into the equation
Your answer is x = 2 because when you plug in 2 for x in the equation, you get 25 = 25
The x intrercepts is where the function crosses the x axis; In other words, it is where the output of the function is 0.
In a quadratic, you can start by factoring, if it’s unable to be factored then use the quadratic formula. Also, it is good to use the discriminate.
D= Discrimminate
D>0 2 real solutions
D=0 1 real solution
D<0 2 imaginary solutions.
The discrimminate is the equation/expression under the radical of the quadratic formula. With this formula, it’s not factorable. Using the discriminate it is also seen, as you’ll get a negative in the square root. This is imagenary because you cannot take the root of a negative value, which is why “i” is used to represent the square root of negative one.