What decimal is equivalent to -23/20
1 answer:
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First we find the zeroes so we don't take the integral of negative bits
4x-x²
x(4-x)
zeroes at x=0 and x=4
it opens down
so the part we are interested in is the bit between x=0 and x=4
![\int\limits^4_0 {4x-x^2} \, dx =[2x^2- \frac{1}{3}x^3]^4_0=(32- \frac{64}{3})-(0)= 10.6666666666](https://tex.z-dn.net/?f=%20%5Cint%5Climits%5E4_0%20%7B4x-x%5E2%7D%20%5C%2C%20dx%20%3D%5B2x%5E2-%20%5Cfrac%7B1%7D%7B3%7Dx%5E3%5D%5E4_0%3D%2832-%20%5Cfrac%7B64%7D%7B3%7D%29-%280%29%3D%20%2010.6666666666)
or aout 10 and 2/3
C is answer
4x-x²
x(4-x)
zeroes at x=0 and x=4
it opens down
so the part we are interested in is the bit between x=0 and x=4
C is answer
The notation in its current form isn't entirely clear.
Did you mean to write ? The 4 isn't in the square root.
If so, then the expression is in simplest form because we cannot simplify any further (note how 10 doesn't have any perfect square factors other than 1).
Also, the 3/4 portion is fully reduced already.
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Or,
Did you mean to write ? This time the 4 is inside the square root.
If so, then we can simplify like this
This means that