Answer:
33232
Step-by-step explanation:
Answer:
<h2>D</h2>
The cube of twice a number decreased by 11
2x+y=-10
Multiply both side by 3
2x*3+y*3=-10*3
6x+3y=-30
3x-y=0
Multiply both side by 2
3x*2-y*2=0*2
6x-2y=0
Next, use substitute property
6x+3y=-30
-
6x-2y=0
=
y=-30
3x-y=0
Substitute y with -30
3x-30=0
Add 30 to each side
3x-30+30=0+30
3x=30
Divided both side by 3
3x/3=30/3
x=10, so the solution pair is (10,-30). In this case, there is the first way to solve these two equation.
Then, I would use equation 3x+1.5y=-15 in this question by multiply 2x+y=-10 by multiplying both side by 3/2 to eliminate x and to solve variables for y. Hope it help!
It would happen again at 1 hour and 5 minutes .
That is because at noon it is 12 p.m. and for the minute and the hour hands overlap, the next time it would happen is at 1:05 which is going to overlap again
<span>3x=7y+16
15y=7y + 16
15y - 7y = 16
8y = 16
y = 8/16
y = 2
hope this helps you !!! =')</span>
