Let width = w
Let length = l
Let area = A
3w+2l=1200
2l=1200-3w
l=1200-3/2
A=w*l
A=w*(1200-3w)/2
A=600w-(3/2)*w^2
If I set A=0 to find the roots, the maximum will be at wmax=-b/2a which is exactly 1/2 way between the roots-(3/2)*w^2+600w=0
-b=-600
2a=-3
-b/2a=-600/-3
-600/-3=200
w=200
And, since 3w+2l=1200
3*200+2l=1200
2l = 600
l = 300
The dimensions of the largest enclosure willbe when width = 200 ft and length = 300 ft
check answer:
3w+2l=1200
3*200+2*300=1200
600+600=1200
1200=1200
and A=w*l
A=200*300
A=60000 ft2
To see if this is max area change w and l slightly but still make 3w+2l=1200 true, like
w=200.1
l=299.85
A=299.85*200.1
A=59999.985
1/6 because the first number that you roll doesn't matter so it depends on the 2nd roll, in which the probability of rolling a specific number is 1/6
Ratio of cat : to dog = 40 : 20 = 2:1
Answer:
b=12
Step-by-step explanation:
3b +24= b +48
-24 -24
3b = b+ 24
-b -b
2b = 24
÷2 ÷2
b=12
- Trapezoid
The measures of three angles of a quadrilateral are 70, 125, and 89 degrees. Find the measure of the fourth one.
》The measure of the fourth one is 36°.
<h3>HOPE ITS HELP</h3>