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ddd [48]
3 years ago
11

Only answer this if you have an explanation and if you know what the answer is.

Mathematics
2 answers:
andrey2020 [161]3 years ago
6 0
B I hope you get this keep up the great work
Rzqust [24]3 years ago
3 0

Answer:

B. 3

Step-by-step explanation:

You can use online calculators for this like symbolab.com for steps! Here is your specific question answered with steps: https://www.symbolab.com/solver/step-by-step/%206%20%E2%88%92%203%5E%7B3%7D%20%5Cdiv%5Cleft(2%5E%7B2%7D%20%2B%205%5Cright)%20

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What is the equation of a line with slope -3 through the point (3, 5)?
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y = -3x + 5

Step-by-step explanation:

4 0
2 years ago
Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

The above equation can be better expressed as:

y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

p(x) = \dfrac{(x+2)}{(x^2-4)^2} \

p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \

p(x) = \dfrac{1}{(x+2)(x-2)^2}

Also;

q(x) = \dfrac{7}{(x^2-4)^2}

q(x) = \dfrac{7}{(x+2)^2(x-2)^2}

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{1}{(x-2)^2}

\implies \dfrac{1}{16}

\lim \limits_{x \to-2} (x+ 2)^2 q(x) =  \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{7}{(x-2)^2}

\implies \dfrac{7}{16}

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0
3 years ago
PLZ HELP WILL MAKE BRAINLEIST
Jlenok [28]
(1,2)
The solution is where the lines intersect so you can see they intersect at (1,2)
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2 years ago
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