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ivolga24 [154]
3 years ago
8

Helppppppppp i m on my test

Mathematics
1 answer:
blondinia [14]3 years ago
4 0
3x+75=180( cause supplementary angles)
-75 -75
3x=105
3x/3= 105/3
x=35

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Ginger makes pies and sells them for $14 each. Write an equation that represents the situation, if y represents the money that G
Andrei [34K]
Y = 14x is the equation you should use! Hope this helped.
8 0
3 years ago
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kondaur [170]

Answer:

<em>Karim will never have triple age as his brother, it has happened already 1 year ago, thus he won't give him a gift</em>

Step-by-step explanation:

<u>Equations</u>

Let's make:

x = the number of years from now

Karim now is 22 and Ziad is 8. x years from now Karim will be

22 + x years old and Ziad will be

8 + x years old.

Karim will give Ziad a wonderful gift when:

22 + x = 3(8 + x)

22 + x = 24 + 3x

Solving:

x = -1

This means that Karim will never have triple age as his brother, it has happened already 1 year ago, thus he won't give him a gift

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2 years ago
A card is selected at random from a deck of cards. What is the probability of randomly selecting a diamond or a 7?
Dominik [7]

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your answer is 4/13ths. #markasbrainliest

7 0
2 years ago
Find the equation for the circle with a diameter whose endpoints are (-5, -3) and (3,2).
densk [106]

Answer:

  (x +1)^2 +(y +0.5)^2 = 22.25

Step-by-step explanation:

The center of the circle is the midpoint of the diameter, so is ...

  (h, k) = ((-5, -3) +(3, 2))/2 = (-5+3, -3+2)/2 = (-1, -1/2)

The circle formula is then ...

  (x -h)^2 +(y -k)^2 = r^2

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We can find r^2 by substituting one of the points for (x, y).

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Then the circle equation is ...

  (x +1)^2 +(y +0.5)^2 = 22.25

3 0
3 years ago
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Rufina [12.5K]
x is in quadrant I, so 0, which means 0, so \dfrac x2 belongs to the same quadrant.

Now,

\tan^2\dfrac x2=\dfrac{\sin^2\frac x2}{\cos^2\frac x2}=\dfrac{\frac{1-\cos x}2}{\frac{1+\cos x}2}=\dfrac{1-\cos x}{1+\cos x}

Since \sin x=\dfrac5{13}, it follows that

\cos^2x=1-\sin^2x\implies \cos x=\pm\sqrt{1-\left(\dfrac5{13}\right)^2}=\pm\dfrac{12}{13}

Since x belongs to the first quadrant, you take the positive root (\cos x>0 for x in quadrant I). Then

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\tan x is also positive for x in quadrant I, so you take the positive root again. You're left with

\tan\dfrac x2=\dfrac15
4 0
3 years ago
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