Btw the bit at the top thats cut off says fence is 15

Mathematics

1 answer:

solmaris [256]3 years ago

5 0

Answer:

47.4 pounds

Step-by-step explanation:

First, find the height of the trapezoid. Draw the height DE. Quadrilateral ABED is a rectangle, then BE = 12 cm. Since BC = 20 cm, then EC = 20 - 12 = 8 cm.

Consider right triangle DEC. By the Pythagorean theorem,

$DE^2+EC^2=CD^2\\ \\DE^2+8^2=17^2\\ \\DE^2=289-64\\ \\DE^2=225\\ \\DE=15\ cm$

The area of the trapezoid ABCD is

$A=\dfrac{AD+BC}{2}\cdot DE=\dfrac{12+20}{2}\cdot 15=16\cdot 15=240\ cm^2$

One can cover $100\ cm^2$ , then it is needed

$\dfrac{240}{100}=2.4$ cans

One can costs 19.75 pounds, then 2.4 cans cost

$19.75\cdot 2.4=47.4$ pounds

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The points J (-13,10) and K(-1,-6) are endpoints of a diameter of circle G. What is the equation of circle G?

In-s [12.5K]

The correct answer is D

The equation of a circle is (x-h)^2 + (y-k)^2 = r^2

to find (h,k), you find the middle of the circle, in this scenario you do so by finding the middle of the diameter, a line that goes through the center of the circle.

To find the X value of the midpoint, add both x values together and divide by 2 and repeat for y

-13 + -1 = -14
-14/2 =-7

10+ -6 = 4
4/2 = 2

therefore (h,k) = ( -7, 2 )

Next plug these values in the equation of a circle

(x-h)^2 + (y-k)^2 = r^2

becomes

(x- (-7)) ^2 + (y-(2)) ^2 = r^2

to find r, use the distance formula to find the length of the diameter, 20, and divide by 2

plug 10 in for r and you get 100

(x+7)^2 + (y-2)^2 = 100

sorry for the late response

7 0

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<h2>Answer:</h2>

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