Answer:
(x, y) (1,5.5) , (2,5.75) (3,5.83) (4,5.875) (5,5.9)
Step-by-step explanation:
The x values lie on the horizontal line and the y values lie on the vertical line.
In order to find the value of y you must substitute the value of x in the equation given and you must plot you graph using the answers you got which I wrote for you.
NOTE:if there's anything you don't understand let me know.
Answer:
<em>The fraction of the beads that are red is</em>
Step-by-step explanation:
<u>Algebraic Expressions</u>
A bag contains red (r), yellow (y), and blue (b) beads. We are given the following ratios:
r:y = 2:3
y:b = 5:4
We are required to find r:s, where s is the total of beads in the bag, or
s = r + y + b
Thus, we need to calculate:
![\displaystyle \frac{r}{r+y+b} \qquad\qquad [1]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Br%7D%7Br%2By%2Bb%7D%20%20%20%20%20%20%20%5Cqquad%5Cqquad%20%20%20%20%5B1%5D)
Knowing that:
![\displaystyle \frac{r}{y}=\frac{2}{3} \qquad\qquad [2]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Br%7D%7By%7D%3D%5Cfrac%7B2%7D%7B3%7D%20%20%20%20%20%20%5Cqquad%5Cqquad%20%20%20%20%5B2%5D)

Multiplying the equations above:

Simplifying:
![\displaystyle \frac{r}{b}=\frac{5}{6} \qquad\qquad [3]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Br%7D%7Bb%7D%3D%5Cfrac%7B5%7D%7B6%7D%20%20%20%20%20%20%20%5Cqquad%5Cqquad%20%20%20%20%5B3%5D)
Dividing [1] by r:

Substituting from [2] and [3]:

Operating:



The fraction of the beads that are red is 
Answer:
The rate of the runner is 3.5 meters per second.
Step-by-step explanation:
To get this answer in meters per second, we first have to convert each of the terms into either meters or seconds. We can do that by multiplying by unit rates.
21 km * 1000 = 21,000 meters
1 hour * 3600 = 3,600 seconds
40 minutes * 60 = 2,400 seconds
Now we divide the meters by the total number of seconds to get the rate.
21,000 meters / (3,600 + 2,400) secs
21,000 meters / 6,000 secs
3.5 meters per second.
B. Yes it's an exponential function because the y is increasing rapidly without a constant rate of change