Rounded it is 11.7 cubic cm.
Answer:
12x7 4 times add it up u got the anwser
Answer:
A line segment is <u><em>always</em></u> similar to another line segment, because we can <u><em>always</em></u> map one into the other using only dilation a and rigid transformations
Step-by-step explanation:
we know that
A<u><em> dilation</em></u> is a Non-Rigid Transformations that change the structure of our original object. For example, it can make our object bigger or smaller using scaling.
The dilation produce similar figures
In this case, it would be lengthening or shortening a line. We can dilate any line to get it to any desired length we want.
A <u><em>rigid transformation</em></u>, is a transformation that preserves distance and angles, it does not change the size or shape of the figure. Reflections, translations, rotations, and combinations of these three transformations are rigid transformations.
so
If we have two line segments XY and WZ, then it is possible to use dilation and rigid transformations to map line segment XY to line segment WZ.
The first segment XY would map to the second segment WZ
therefore
A line segment is <u><em>always</em></u> similar to another line segment, because we can <u><em>always</em></u> map one into the other using only dilation a and rigid transformations
Answer:
AD = 1/4AC
Step-by-step explanation:
Given that,
D is the the midpoint of AB
Therefore
AB = AD + DB
Since, D is the midpoint of the AB, therefore AD = DB
AB = AD + AD
AB = 2AD (i)
Similarly, B is the midpoint of AC
Hence,
AC = AB + BC
AC = AB + AB (because B is the midpoint)
AC = 2AB (ii)
By putting the value of AB from equation i to equation ii, we get
AC = 2(2AD)
AC = 4AD
AC/4 = AD
AD = 1/4AC
Answer:
15) K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]
19) P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]
20) Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)
Step-by-step explanation:
We are to find the derivative of the questions pointed out.
15) K(t) = 5(5^(t)) - 2(3^(t))
Using implicit differentiation, we have;
K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]
19) P(w) = 2e^(w) - (2^(w))/5
P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]
20) Q(W) = 3w^(-2) + w^(-2/5) - w^(¼)
Q'(w) = -6w^(-2 - 1) + (-2/5)w^(-2/5 - 1) - ¼w^(¼ - 1)
Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)
