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Hoochie [10]
3 years ago
14

If $20.00 is for 12.25kg of peas ...what weight of peas can i get for $4.00​

Mathematics
1 answer:
Alina [70]3 years ago
4 0

2.45kg

First you calculate the price per kg as follows:

If it’s $20 for 12.25 kg, the price per kg is $20/12.25=$1.63 per kg


If you have $4, you can figure out what weight you can get by taking $4/the price per kg, so $4/$1.63, which is 2.45 kg.

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Abby, Bik, Cari, Dawn, and Ellen collect T-shirts. Abby has the most. Bik has 2.5 times as many T-shirts as Cari. Dawn has 1/3 a
bixtya [17]
A=abby's shirts
b=bik's shirts
c=cari's shirts
d=dawn's shirts
e=ellen's shirts


a> everybody
b=2.5c
d=(1/3)c
a+b+c+d=120
e=2d+1
e=13
oook

e=13=2d+1
13=2d+1
12=2d
d=6

d=(1/3)c
6=(1/3)c
18=c

b=2.5c
b=2.5(18)
b=45

a+b+c+d=120
a+45+18+6=120
a+69=120
a=51
4 0
2 years ago
An amount of $25,000 is borrowed for 9 years at 9% interest, compounded annually. If the loan is paid in full at the end of that
Natasha_Volkova [10]

Please do not spam the same question, I have already answered it.

3 0
3 years ago
PLEASE HELPP NOW!!!!!
BaLLatris [955]

Answer:

the codrect answer is 625

3 0
2 years ago
Read 2 more answers
Which expression has a value of 1/36?
Nataly [62]

Answer:

1/36) = 0.0277777777778

(1/108)^3 = 7.9383224102 x 10^-7

(1/9)^4 = 0.000152415790276

(1/6)^2 = 0.0277777777778

(1/2)^5 = 0.03125

The only one that matches with the value of 1/36 is (1/6)^2. Therefore, your answer is . (1/6)^2

8 0
1 year ago
If a 24-kg mass stretches a spring 15 cm, what mass will stretch the spring 10 cm
natulia [17]

Answer:

<h2>16kg</h2>

Step-by-step explanation:

 This problem is borers on elasticity of materials.

according to Hooke's law,<em> "provided the elastic limit of an elastic material is not exceeded the the extension e is directly proportional to the applied force."</em>

F= ke

where F is the applied force in N

          k is the spring constant N/m

          e is the extension in meters

Given data

mass m= 24kg

extensnion=15cm in meters= \frac{15}{100}= 0.15m

we can solve for the spring constant k

we also know that the force F = mg

assuming g=9.81m/s^{2}

therefore

24*9.81=k*0.15\\235.44=k*0.15\\k=\frac{235.44}{0.15} \\k=1569.6N/m\\

We can use this value of k to solve for the mass that will cause an extension of  10cm= 0.1m

x*9.81=1569.6*0.1\\\\x= \frac{156.96}{9.81} \\\x= 16kg

5 0
3 years ago
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