Ask question

Ask question

All categories

3 years ago

7

juan can walk to school a distance of 1 mile, in 12 minutes . assuming he walks at a constant rate what is Juan’s constant speed

? write a linear equation in two variables to represent Juan’s constant speed.

1 answer:

Tomtit [17]3 years ago

4 0

Answer:

1 mile every 12 miniutes

Step-by-step explanation:

ratio table will help you

You might be interested in

N/4 + 12 =18 i will give brainllest

Hoochie [10]

Answer:

n = 24

Step-by-step explanation:

subtract 12

n/4 = 6

multiply by 4

n = 24

7 0

2 years ago

Read 2 more answers

E = MV^2 ÷ 2 + mgh, Make V Subject of the formula

Stels [109]

Answer:

$\red{ \bold{ V = \sqrt{\frac{2(E - mgh)}{M}}}}$

Step-by-step explanation:

$E = MV^2 ÷ 2 + mgh \\ \\ E - mgh = MV^2 ÷ 2 \\ \\ 2(E - mgh)= MV^2 \\ \\ \frac{2(E - mgh)}{M}=V^2 \\ \\ \sqrt{\frac{2(E - mgh)}{M}} = V \\ \\ \red{ \bold{ V = \sqrt{\frac{2(E - mgh)}{M}}}}$

4 0

3 years ago

The following information is given for Tripp Company, which uses the indirect<br> method

oee [108]

Answer:

Step-by-step explanation:

1.

The cash flow from operating activities is = $28000.

Working Note:

Net Income $20000

Depreciation expense $3000

Increase in accounts receivable ($2000)

Increase in accounts payable $4000

Decrease in inventory $3000

Net Cash Flow from Operating Activities = 20000 + 3000 – 2000 + 4000 + 3000

Net Cash Flow from Operating Activities = $28000

2.

The cash flow from investing activities = $6000.

Working Note:

Proceeds from sale of equipment $6000

Net cash flow from investing activities = $6000

3.

The cash flow from financing activities = - $2000 or ($2000)

Working Note:

Payment of dividends ($2000)

Net Cash flow from financing activities = - $2000 or ($2000)

7 0

2 years ago

One side of trapezoid is 10 inches. The side parrellel to this is twice as long as this side. The height is half as long as the

madam [21]

The first side is 10 inches
the side parallel to this is (10×2)= 20 inches
Height is half the length=1/2×20=10 inches
The area of trapezium is given by:
Area=1/2×h×(a+b)
where a and b are the sides, h is the height. Thus the area will be:
Area=1/2×10×(20+10)
=1/2×10×30
=150 sq. inches

7 0

3 years ago

What is a correct congruence statement for the triangles shown? Enter your answer in the box. △QDJ≅△ A triangle Q D J. The b

almond37 [142]

Answer: The correct congruence statement is $\triangle QDJ\cong \triangle MCW$ .

Explanation:

It is given that A triangle Q D J. The base D J is horizontal and side Q D is vertical. Another triangle M C W is made. The base C W and side M C are neither horizontal nor vertical. Triangle M C W is to the right of triangle Q D J.

The sides Q D and M C are labeled with a single tick mark. The sides D J and C W are labeled with a double tick mark. The sides Q J and M W are labeled with a triple tick mark.

Draw two triangles according to the given information.

From the figure it is noticed that

$QD\cong MC$

$DJ\cong CW$

$QJ\cong MW$

So by SSS rule of congruence we can say that $\triangle QDJ\cong \triangle MCW$ .

4 0

2 years ago

Read 2 more answers