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posledela
3 years ago
14

My question is im trying to solve for y in this problem 20x - 12y = -108​

Mathematics
1 answer:
ziro4ka [17]3 years ago
4 0

Answer:y=  \frac{5}{3} x + 9

Step-by-step explanation:

20x - 12y = -108

Add 12y + 108 to both sides

​12y = 20x + 108

Divide both sides by 12

y = \frac{20}{12} x + \frac{108}{12}\\y=  \frac{5}{3} x + 9

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<img src="https://tex.z-dn.net/?f=%5Csqrt%7B272%7D" id="TexFormula1" title="\sqrt{272}" alt="\sqrt{272}" align="absmiddle" class
lozanna [386]

√272 is a real number, and the simplified expression of √272 is 4√17

<h3>How to simplify the expression?</h3>

The expression is given as:

√272

Expand

√272 = √16 * 17

Take the square root of 16

√272 = 4√17

Hence, the simplified expression of √272 is 4√17

Read more about real numbers at:

brainly.com/question/7784687

#SPJ1

7 0
2 years ago
I can't figure out how to do (i + j) x (i x j)for vector calc
Vinil7 [7]

In three dimensions, the cross product of two vectors is defined as shown below

\begin{gathered} \vec{A}=a_1\hat{i}+a_2\hat{j}+a_3\hat{k} \\ \vec{B}=b_1\hat{i}+b_2\hat{j}+b_3\hat{k} \\ \Rightarrow\vec{A}\times\vec{B}=\det (\begin{bmatrix}{\hat{i}} & {\hat{j}} & {\hat{k}} \\ {a_1} & {a_2} & {a_3} \\ {b_1} & {b_2} & {b_3}\end{bmatrix}) \end{gathered}

Then, solving the determinant

\Rightarrow\vec{A}\times\vec{B}=(a_2b_3-b_2a_3)\hat{i}+(b_1a_3+a_1b_3)\hat{j}+(a_1b_2-b_1a_2)\hat{k}

In our case,

\begin{gathered} (\hat{i}+\hat{j})=1\hat{i}+1\hat{j}+0\hat{k} \\ \text{and} \\ (\hat{i}\times\hat{j})=(1,0,0)\times(0,1,0)=(0)\hat{i}+(0)\hat{j}+(1-0)\hat{k}=\hat{k} \\ \Rightarrow(\hat{i}\times\hat{j})=\hat{k} \end{gathered}

Where we used the formula for AxB to calculate ixj.

Finally,

\begin{gathered} (\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=(1,1,0)\times(0,0,1) \\ =(1\cdot1-0\cdot0)\hat{i}+(0\cdot0-1\cdot1)\hat{j}+(1\cdot0-0\cdot1)\hat{k} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=1\hat{i}-1\hat{j} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=\hat{i}-\hat{j} \end{gathered}

Thus, (i+j)x(ixj)=i-j

8 0
1 year ago
The radius of a circle is (7n-21) inches find circumference of the circle in terms of n.
hodyreva [135]

Answer:

(14n - 42)*pi

Step-by-step explanation:

Circumference is 2 * pi * r. Since r in this case is 7n - 21, you can multiply r by 2 and pi, giving you (14n - 42)*pi

4 0
4 years ago
If y = 124 and x = 12, find y when x = -24.
tatyana61 [14]

Answer:

y = -248

Step-by-step explanation:

Hi there!

Set up a proportion:

\displaystyle\frac{124}{12} =\frac{y}{-24}

Cross-multiply:

12y=(-24)(124)\\12y=-2976\\y=-248

I hope this helps!

7 0
3 years ago
What the vertex of the equation: y = x^2 - 6x + 11
pychu [463]

Answer:

the vertex is of the equation is (3,2)

7 0
3 years ago
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