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mart [117]
3 years ago
9

after allowing 15% discount on the price of an article and 13% bat was live and the remaining amount in the price of article bec

omes 13447 find the market price of an article​
Mathematics
1 answer:
Eduardwww [97]3 years ago
5 0

Answer:

14000

Explaination:

spwithvat = sp without vat + 13% of sp without vat

let, sp without vat be x.

sp with vat= x + 13% of x.

or, 13447 = x + 13/100 × x

or, 1344700 = 113x

or, x= 1344700/113

x = 11900

Let, mp be y.

sp with vat = mp - 15% of mp

or, 11900 = y - 15/100 × y

or, 1190000 = 85y

or, y= 1190000/85

y= 14000

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Carol is cross country skiing the table shows the distance traveled after various numbers of minutes what is the rate of change
MatroZZZ [7]

Answer:

Option D 3/16

Step-by-step explanation:

Carol is cross-country skiing.

With the help of the given table we have to calculate the rate of change.

If we draw a graph for distance traveled on y-axis and tins at x-axis we find two points, ( 2, 1/6) and (3, 17/48).

Then slope of the line connecting these points will be the rate of change.

8 0
3 years ago
How to find the sum of 2+4+6....+40?
grandymaker [24]
Answer 420.
a, is the first term. d is difference.
Since this is an arithmetic progression, I use this formula.
Un = nth term
Sn = sum of terms.
First find the number of terms, which is 20.
Then use the second formula to find the sum.

3 0
3 years ago
The circumference of a circular rug is 24.8 meters. What is the area of the rug? Use 3.1 for pi
pochemuha

Answer:

49.6 square meters

Step-by-step explanation:

first, circumference is 2*pi*r, so we want to find r.  so we take 2*pi*r=24.8 and solve for r which is 4.

Now, area is pi*r^2 so pi*4^2 = pi*16 = 49.6

7 0
3 years ago
Read 2 more answers
1) find the equation of the line parallel to
In-s [12.5K]

<u>Answer:</u>

1) The equation of the line parallel to  x-5y=6 and through (4,-2) is 5y = x -14

2) The equation of the line perpendicular to y= -2/5x + 3 and through (2,-1) is  2y = 5x -12

<u>Solution:</u>

<u><em>1) find the equation of the line parallel to  x-5y=6 and through (4,-2).</em></u>

Given, line equation is x – 5y = 6  

We have to find the line equation that is parallel to given line and passing through the point (4, -2)

Now, let us find slope of the given line.

\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-5}=\frac{1}{5}

Now, we know that, slope of parallel lines are equal.

So, slope of required line is 1/5 and it passes through (4, -2)

Now, using point slope form

y-y_{1}=m\left(x-x_{1}\right) \text { where } m \text { is slope and }\left(x_{1}, y_{1}\right) \text { is point on line. }

y-(-2)=\frac{1}{5}(x-4) \rightarrow 5(y+2)=x-4 \rightarrow 5 y+10=x-4 \rightarrow x-5 y=14

Hence, the line equation is 5y = x -14

<u><em> 2) find the equation of the line perpendicular to y= -2/5x + 3 and through (2,-1)</em></u>

\text { Given, line equation is } y=-\frac{2}{5} x+3 \rightarrow 5 y=-2 x+15 \rightarrow 2 x+5 y=15

We have to find the line equation that is perpendicular to given line and passing through the point (2, -1)

Now, let us find slope of the given line.

\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-2}{5}=-\frac{2}{5}

Now, we know that, product of slopes of perpendicular lines equals to -1.

So, slope of required line \times slope of given line = -1

slope of required line = -1 \times \frac{5}{-2}=\frac{5}{2}

And it passes through (2, -1)

Now, using point slope form

\begin{array}{l}{\text { Line equation is } y-(-1)=\frac{5}{2}(x-2) \rightarrow 2(y+1)=5(x-2)} \\\\ {\rightarrow 2 y+2=5 x-10 \rightarrow 5 x-2 y=12}\end{array}

Hence, the line equation is 2y = 5x -12

4 0
3 years ago
What does m equal?please help me.
algol13

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the inequalities.

===> -7 + 45m - 35 < 9m - 11

===> 45m - 42 < 9m - 11

===> 45m - 9m < -11 + 42

==> 36m < 31

==> m < 31/36

hence the value of m < 31/36

6 0
3 years ago
Read 2 more answers
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