<em>=</em><em>5</em><em>^</em><em>6</em><em>/</em><em>5</em><em>^</em><em>4</em>
<em>=</em><em>5</em><em>^</em><em>(</em><em>6</em><em>-</em><em>4</em><em>)</em>
<em>=</em><em>5</em><em>^</em><em>2</em><em> </em><em>ANSWER</em><em>.</em><em>.</em>
1. 35x + 0.15y
=3500x + 15y [multiplying the equation by 100]
= 700x + 3y [dividing the equation by 5]
2. Let x be an even integer
x + (x+2) + (x+2+2)
x+x+2+x+4
3x+6
3. 1/5*(r+7) - 9s
(r+7)/5 - 9s
4. x=cows
y= goats + sheep
x= (y+140)/2
Answer:
STEP ONE: 2x
STEP TWO: 5=X (should be the final answer)
Step-by-step explanation:
Hi Lasagna!
So basically, this is extremely simple. In order to "solve" that equation, the x has to be on one side. The easiest way to do this would be to take the 2x to the other side. If you want the 2x to go to the other side, you need to subtract it (since it is already positive, therefore it <em>needs </em>to cancel out). Once you do that, you must always do the same thing to the other side: subtract 2x from 3x. That should get you one x there, which you can just write as x if it's just one. Then you're all set! :D
Primary equation: A(x)= (5y)(3X)
Secondary equation: 5y+3X=1000
y=200-(3X)/5
A(x)=3X(1000-3X)
A(x)=3000X-9X²
Now, find the derivative of A(x) to find the max... here's the work for that, or you could guess and check.
A'(x)=3000-18X
Set derivative equal to 0
0=3000-18X
166.6666666=X
Now test the intervals
(0,166.6666) (166.66666, 1000)
1st derivative is + 1st derivative is -
Plug the X value back into the secondary equation
5y+3(166.666666)=1000
5Y=500
Y=5
Answer:
X= 166.6666666666
Y=5
Please note, this is entry level calculus, and your teacher may expect you to use a different, longer route such as guess and check.
