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Vladimir79 [104]
2 years ago
13

Solve the picture, solve n

Mathematics
1 answer:
Molodets [167]2 years ago
6 0

Answer: n = 63

Step-by-step explanation:

n ÷ 21 = 3

Do the opposite to find n!

3 × 21 = 63

So, to check our answer

63 ÷ 21 = 3

n = 3

:))

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I put all of my points down<br> SOME PLEASE HELP ASAP<br> THANKS!
Vinvika [58]

The chain made 145 times more money than the single store.

To find this answer first find the amount of money both made and divide the chain amount by the super store amount to get the final answer.


Hope this helps. :D

3 0
3 years ago
2. Find the Median Average of these quiz scores:<br>93, 79, 83, 89, 90, 71, 85, 93, 88, 86​
steposvetlana [31]

Answer:

90 and 71 or 80.5

Step-by-step explanation:

find middle two numbers

add them together

divide by 2

3 0
2 years ago
Read 2 more answers
Help me, please!!!!!!!!!​
NISA [10]

Step-by-step explanation:

part A

y=nx

part B

y=48×x

y=48x

4 0
2 years ago
NO LINKS!!! Part 2: Find the Lateral Area, Total Surface Area, and Volume. Round your answer to two decimal places.​
slava [35]

Answer:

<h3><u>Question 7</u></h3>

<u>Lateral Surface Area</u>

The bases of a triangular prism are the triangles.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the triangles (bases).

\implies \sf L.A.=2(10 \times 6)+(3 \times 6)=138\:\:m^2

<u>Total Surface Area</u>

Area of the isosceles triangle:

\implies \sf A=\dfrac{1}{2}\times base \times height=\dfrac{1}{2}\cdot3 \cdot \sqrt{10^2-1.5^2}=\dfrac{3\sqrt{391}}{4}\:m^2

Total surface area:

\implies \sf T.A.=2\:bases+L.A.=2\left(\dfrac{3\sqrt{391}}{4}\right)+138=167.66\:\:m^2\:(2\:d.p.)

<u>Volume</u>

\sf \implies Vol.=area\:of\:base \times height=\left(\dfrac{3\sqrt{391}}{4}\right) \times 6=88.98\:\:m^3\:(2\:d.p.)

<h3><u>Question 8</u></h3>

<u>Lateral Surface Area</u>

The bases of a hexagonal prism are the pentagons.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the pentagons (bases).

\implies \sf L.A.=5(5 \times 6)=150\:\:cm^2

<u>Total Surface Area</u>

Area of a pentagon:

\sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}a^2

where a is the side length.

Therefore:

\implies \sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}\cdot 5^2=43.01\:\:cm^2\:(2\:d.p.)

Total surface area:

\sf \implies T.A.=2\:bases+L.A.=2(43.01)+150=236.02\:\:cm^2\:(2\:d.p.)

<u>Volume</u>

\sf \implies Vol.=area\:of\:base \times height=43.011193... \times 6=258.07\:\:cm^3\:(2\:d.p.)

8 0
1 year ago
Which of the following CANNOT be given the lengths of the sides of a triangle?
Katena32 [7]

The sides of a triangle must satisfy the triangle inequality, which states the sum of the lengths of any two sides is strictly greater than the length of the remaining side.  

We really only have to check if the sum of the two smaller sides exceeds the largest side.

A. 5+6>7, ok

B. 6+6>10, ok

C. 7+7=14 Not ok, this is a degenerate triangle not a real triangle

D. 4+6>8 ok

Answer: C

6 0
3 years ago
Read 2 more answers
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