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tankabanditka [31]
2 years ago
9

Write an equation in point-slope form for the line that passes through (–2, 1) with a slope of 1/4

Mathematics
1 answer:
Anna11 [10]2 years ago
5 0

Answer:

5

Step-by-step explanation:

The point-slope equation of the line that passes through the point (2,1) and has the slope 5 , is y−1=5(x−2) . The generic equation for point-slope form is y−y1=m(x−x1) , where m is the slope and x1 and y1 are the given point.

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6 0
3 years ago
Read 2 more answers
I WILL GIVE A FREAKING BRAINLIEST!!!!!!!!!!!
UkoKoshka [18]

Answer:

  0.5 < t < 2

Step-by-step explanation:

The function reaches its maximum height at ...

  t = -b/(2a) = -16/(2(-16)) = 1/2 . . . . . . where a=-16, b=16, c=32 are the coefficients of f(t)

The function can be factored to find the zeros.

  f(t) = -16(t^2 -1 -2) = -16(t -2)(t +1)

The factors are zero for ...

  x = -1 and x = +2

The ball is falling from its maximum height during the period (0.5, 2), so that is a reasonable domain if you're only interested in the period when the ball is falling.

5 0
3 years ago
Solve the equation x+1&lt;5<br> #
OLEGan [10]
It's the inequality.

x+1
7 0
3 years ago
Solve the following system of equations: −2x + y = 1 −4x + y = −1
Katyanochek1 [597]

Answer:

<h2>x = 1, y = 3 → (1, 3)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}-2x+y=1\\-4x+y=-1&\text{change the signs}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-2x+y=1\\4x-y=1\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad2x=2\qquad\text{divide both sides by 2}\\.\qquad x=1\\\\\text{Put it to the first equation:}\\\\-2(1)+y=1\\-2+y=1\qquad\text{add 2 to both sides}\\y=3

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3 years ago
Please help me!!!!!!! It's very important!!!!
qwelly [4]
You could just use 3.14 or 22/7
6 0
3 years ago
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