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4 years ago

Determine which of the mapping diagrams represents a relation that is not a function.

Mathematics

1 answer:

Andrej [43]4 years ago

8 0

Answer:

See attachment

Step-by-step explanation:

The relation that is not a function is shown in the attachment.

For a relation to be a function, it must be either one-to-one or many-to-one.

The relation shown in the attachment is one-to-many relation hence it is not a function.

This is because -5 corresponds to -4 and 3,making the graph of this relation to fail the vertical line test.

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School yearbooks were printed and the table shows the number of people who bought them the first, second, third, and fourth week

nadya68 [22]

Answer: The correct graph that would depict the table correctly would be the first one listed. There is a sudden increase in the last day which would cause the graph to curve. Hope this helps you out! If you need anything else I'm here to help.

4 0

3 years ago

It costs $109 per night to rent a motel room in Georgia. There is a one-time $30 non-refundable deposit required. How much will

Ne4ueva [31]

Answer:

$793.00

Step-by-step explanation:

109x7=763

763+30=793

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3 years ago

Read 2 more answers

Suppose y varies directly as x, and y=14 when x=4. What is the value of y when x=9

Katena32 [7]

Given :-

y varies directly as x, and y=14 when x=4.

To Find :-

the value of y when x=9 .

Solution :-

According to Question ,

y = kx ( k is constant )

When y = 14 and x = 4 ,

14 = k(4)
k = 14/4
k = 7/2

When x = 9 ,

y = 7/2*9
y = 63/2
y = 31.5

8 0

3 years ago

Are the solutions correct?

Aloiza [94]

Answer:

First one is wrong. x should be 16.

Second one is not completely visible, so cannot say.

Step-by-step explanation:

In the last step, the divison by 4 yields:

x/16 = 1, so x = 16

4 0

3 years ago

Marine biologists have determined that when a shark detectsthe presence of blood in the water, it will swim in the directionin w

siniylev [52]

Solution :

a). The level curves of the function :

$C(x,y) = e^{-(x^2+2y^2)/10^4}$

are actually the curves

$e^{-(x^2+2y^2)/10^4}=k$

where k is a positive constant.

The equation is equivalent to

$x^2+2y^2=K$

$\Rightarrow \frac{x^2}{(\sqrt K)^2}+\frac{y^2}{(\sqrt {K/2})^2}=1, \text{ where}\ K = -10^4 \ln k$

which is a family of ellipses.

We sketch the level curves for K =1,2,3 and 4.

If the shark always swim in the direction of maximum increase of blood concentration, its direction at any point would coincide with the gradient vector.

Then we know the shark's path is perpendicular to the level curves it intersects.

b). We have :

$\triangledown C= \frac{\partial C}{\partial x}i+\frac{\partial C}{\partial y}j$

$\Rightarrow \triangledown C =-\frac{2}{10^4}e^{-(x^2+2y^2)/10^4}(xi+2yj),$ and

$\triangledown C$ points in the direction of most rapid increase in concentration, which means $\triangledown C$ is tangent to the most rapid increase curve.