Answer:
- 3.75 bags of ChowChow
- 0.75 bags of Kibble
Step-by-step explanation:
The constraints on protein, minerals, and vitamins give rise to the inequalities ...
40c +30k ≥ 150 . . . . . . required protein
20c +20k ≥ 90 . . . . . . required minerals
10c +30k ≥ 60 . . . . . . . required vitamins
And we want to minimize 10c +12k.
The graph shows the vertices of the feasible region in (c, k) coordinates. The one that minimizes cost is (c, k) = (3.75, 0.75).
To minimize cost, the daily feed should be ...
- 3.75 bags of ChowChow
- 0.75 bags of Kibble
Daily cost will be $46.50.
To find the answer, we multiply 1,047.30 by 6.2% which is 0.062 in percentage.
1047.30 x 0.062 = 64.93
64.93 is being taken away.
It is $57.38 you just multiply it by 1.00 and you get $57.38.
9/4x -15 for x=4
To find this answer you must plug the 4 everywhere the x is located.
(9/4)(4) -15
Multiply 9/4 by 4
(9/4) x 4 = 9
Now we take our 9 answer and add it to -15.
9-15 = -6
The answer is -6
-
-
For the other equation, you also must plug in 3 where ever x is located in the equation.
5/3x -3/5
(5/3)(3) -3/5
Multiply 5/3 and 3
(5/3) x 3 = 5
Take that answer of 5 and add -3/5
5- (3/5) =4 2/5
The answer to this equation would be 4 2/5 or 4.4
Answer:
See Explanation.
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra II</u>
- Log/Ln Property:

<u>Calculus</u>
Derivatives
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Chain Rule: ![\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28g%28x%29%29%5D%20%3Df%27%28g%28x%29%29%20%5Ccdot%20g%27%28x%29)
Derivative of Ln: ![\frac{d}{dx} [ln(u)] = \frac{u'}{u}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bln%28u%29%5D%20%3D%20%5Cfrac%7Bu%27%7D%7Bu%7D)
Step-by-step explanation:
<u>Step 1: Define</u>

<u>Step 2: Differentiate</u>
- Rewrite:

- Rewrite [Ln Properties]:

- Differentiate [Ln/Chain Rule/Basic Power Rule]:

- Simplify:

- Rewrite:

- Combine:

- Reciprocate:

- Distribute:
