The answer here Im sure it’s C(15)
Answer: 3x^2-28x+68
Positive that this is correct
Answer:
7. Down 5
8. Horizontal reflection
9. Vertical stretch by a factor of 5
Step-by-step explanation:
Transformations of Graphs (functions) is the process by which a function is moved or resized to produce a variation of the original (parent) function.
<u>Transformations</u>
For a > 0








Identify the transformations that take the parent function to the given function.
<u>Question 7</u>


Comparing the parent function with the given function, we can see that 5 has been <u>subtracted from the parent function</u>.
Therefore, the transformation is:

<u>Question 8</u>


Comparing the parent function with the given function, we can see that the <u>parent function has been multiplied by -1</u>.
Therefore, the transformation is:

<u>Question 9</u>


Comparing the parent function with the given function, we can see that the <u>parent function has been multiplied by 5.</u>
Therefore, the transformation is:

Learn more about graph transformations here:
brainly.com/question/27845947
Answer:
Yes, multiplying every length of a Pythagorean triple by the same whole number results in a Pythagorean triple.
Step-by-step explanation:
The missing options are:
<em>Yes, multiplying every length of a Pythagorean triple by the same whole number results in a Pythagorean triple. </em>
<em>Yes, any set of lengths with a common factor is a Pythagorean triple. </em>
<em>No, the lengths of Pythagorean triples cannot have any common factors. </em>
<em>No, the given side lengths can form a Pythagorean triple even if the lengths found in step 2 do not.</em>
A Pythagorean triple is a group of three integers (a, b and c) that satisfies the next equation:
c² = a² + b²
Multiplying the three integers by the same positive integer, you would get another Pythagorean triple.
(kc)² = (ka)² + (kb)²
k²c² = k²a² + k²b²
k²c² = k²(a² + b²)
c² = a² + b²
The procedure followed by Leon is the opposite. He found the greatest common factor and divided the given lengths by the greatest common factor, obtaining the simplest Pythagorean triple, which is (3,4,5)