Answer:
180 points.
Step-by-step explanation:
Given:
A class will have 1 test and 5 homework assignments to complete.
The test is worth 80 points.
Each homework assignment is work 25% of the test.
Question asked:
How many points may be earned during this unit ?
Solution:
By unitary method:
Points may be earned from 1 assignments = (given)
=
Points may be earned from 5 assignments =
Points may be earned from 1 test =
Total points may be earned = 100 + 80 = 180
Therefore, 180 points may be earned during this unit.
-1 divided by x
1 - x
X - 1
Answer:
1000000 = 1 MLN CODES
Step-by-step explanation:
According the terms of the problems the code has 6 digits or has 6 positions.
At 1st position any of 10 digits (0,1,2,3,4,5,6,7,8 or 9 ) can put
The digits can repeated, so at position 2 any of 10 difits can put.
At position 3 again any of 10 digits can put and similarly for each of next positions can be put any of 10 digits.
So each position of the code has 10 possible variants.
To find the total number of possible codes we have to multiply the number of variants for each position to each other.
N=10*10*10*10*10*10= 10^6=1 000 000
Initial value is differential equation with a specific value given some point of the domain situation. Hope this helps!
I believe the answer is, not positive though
(-30m+33)