Answer:
Step-by-step explanation:
We are given that
We have to find the value of given logarithms by using change-base formula
Base-change formula:
Where x=New base
Using the formula then, we get
Substitute the values 
Then,we get
<h2>
Speed of plane = 1110 kmph</h2><h2>
Speed of wind = 150 kmph</h2>
Step-by-step explanation:
Let the speed of plane be p and speed of wind be w.
Flying against the wind, an airplane travels 5760 kilometers in 6 hours.
Here
Speed = (p-w) kmph
Time = 6 hours
Distance = 5760 kmph
Distance = Speed x Time
5760 = (p-w) x 6
p-w = 960 -----eqn 1
Flying with the wind, the same plane travels 6300 kilometers in 5 hours.
Here
Speed = (p+w) kmph
Time = 5 hours
Distance = 6300 kmph
Distance = Speed x Time
6300 = (p+w) x 5
p+w = 1260 -----eqn 2
eqn 1 + eqn 2
p-w + p +w = 960 + 1260
2p = 2220
p = 1110 kmph
Substituting in eqn 2
1110 + w = 1260
w = 150 kmph
Speed of plane = 1110 kmph
Speed of wind = 150 kmph
Answer:
∠AOB = 139°
Step-by-step explanation:
The 2 angles form a straight angle and sum to 180°, that is
∠AOB + ∠BOC = 180 ← substitute values
8x + 51 + 6x - 25 = 180, that is
14x + 26 = 180 ( subtract 26 from both sides )
14x = 154 ( divide both sides by 14 )
x = 11
Hence
∠AOB = 8x + 51 = (8 × 11) + 51 = 88 + 51 = 139°
Answer:
y-5=3x-15
Step-by-step explanation:
Slope=(5+1)/(-6+8)
=6/2
=3
Equation of line passing throgh point (-6,5):
y-5=3(x-5)
y-5=3x-15
The ratio of depth to horizontal distance is the tangent of the angle of depression.
250 +tan(15°)*1500 = 651.9 . . . . . feet
