Answer:
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Step-by-step explanation:
1. Multiply x and 3y by x-2
x^2-2x (i.e. x*x=x^2, -2*x=-2x)
3yx-6y (i.e. 3y*x=3yx, 3y*2=6y)
2. Multiply x+y by -4
x*-4= -4x
y*-4=-4y
3. Multiply 2x+3y by -1
2x*-1=-2x
3y*-1=-3y
4. Combine like terms
x^2 3yx -2x -6y
-2x -3y
-4x -4y
-------------------------------------------
x^2 +3yx -8x -13y
Hope this helps!
<span>It might be helpful to remember that the definitions of R2 and R3 are not geometric at all. R2 is the set of all ordered pairs of real numbers, whereas R3 is the set of all ordered triples of real numbers. W is a subspace fo R3, and so it still consists of elements which are triples, not pairs.
The fact that R2 and W can be visualized with the same geometric picture, namely the xy plane, is one way to see in a concrete way the isomorphism which the second poster refered to.</span>
Answer:
<u>3</u><u>z</u><u>^2 + 3z - 6 </u>=0
3
3 (z^2 + z -2) = 0
3(z+2)(z - 1) = 0
z + 2-2 = 0 - 2
z = -2
z - 1 + 1 = 0 + 1
z = 1
Step-by-step explanation:
- factor out the GCF (3) and divide everything by it, and then set it equal to zero.
- since you have a degree of 2, factor it into two binomials that start with the square root of the first term and end with the square root of the second term.
- 3=0 is extraneous solution so we leave it, then we set each binomial equal to zero to solve for z.
note: your solutions is based on the degree or the exponent of the polynomial or the function.
Answer:
The is answer is the last one.
Step-by-step explanation:
I just took the test