Answer:
The owner's profit for a ten-day period is $4675
Step-by-step explanation:
Each day a small business owner sells 200 pizza slices for $1.50 per slice and 85 sandwiches at $3.50 each.
Let's find the revenue.
Revenue = 200($1.50) + 85($3.50)
= $300 + $297.50
Revenue per day = $597.50
Revenue for 10 days = 10($597.50) = $5975
Business expenses per day = $130
Business expenses for 10 days = 10($130) = $1300
Now let's find the profit.
Profit for 10 days = Revenue - Expense
= $5975 - $1300
= $4675
So the owner's profit for a ten-day period is $4675
Try the last one; it doesn't mention anything foreign.
Tamam hocam nasılsınız hocam proje konularını da bir insan değilim ki bir şey olmaz ya o yüzden bir insan bir
var ama ben bir insan bir arar
Answer:
It's A my friend
Step-by-step explanation:
Answer:
Step-by-step explanation:
given is a system of linear equations in 3 variables as
This can be represented in matrix form as
AX=B Or
![\left[\begin{array}{ccc}-1&-4&2\\1&2&-1\\1&1&-1\end{array}\right] *\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}-10\\11\\14\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%26-4%262%5C%5C1%262%26-1%5C%5C1%261%26-1%5Cend%7Barray%7D%5Cright%5D%20%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-10%5C%5C11%5C%5C14%5Cend%7Barray%7D%5Cright%5D)
So solution set
X would be 
|A|=-1(-1)+4(0)+2(-1)=--1
Cofactors of A are
-1 0 -1
-2 -1 -3
0 1 2
So inverse of A is
1 2 0
0 1 -1
1 3 -2
Solution set would be
x=12
y=-3
z=-5
