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N76 [4]
3 years ago
13

Expand and simplify 2(x-4) -3 (x-6)​

Mathematics
1 answer:
Nataly [62]3 years ago
4 0

Answer:

-x + 10

Step-by-step explanation:

Remove the brackets

2*x - 2*4 - 3*x - 3* -6

2x - 8 - 3x + 18

-x + 10

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How to write one times one +nine times (1/100) in standard form
Genrish500 [490]
1*1+9∗0.001


Hope this helps
8 0
3 years ago
Evaluate the expression below when x = 4, y = 5<br><br> 3(y-x) + 4y
likoan [24]

Answer:

23

Step-by-step explanation:

Brackets go first, 5 (y) - 4 (x) = 1. Now, 3 x 1 = 3, you do this because of the 3 next to the brackets. Now add them together.

4 0
3 years ago
The width of a rectangular room is 60 percent of its length. the length of the room is 10 feet. what is the area of the room
blsea [12.9K]
The width is 6 feet because 10•0.6=6
4 0
4 years ago
Read 2 more answers
Please help ! And explain if u can
irga5000 [103]

Answer:

Scalene Triangle

Step-by-step explanation:

If you mark the points on the graph, all three sides have different lengths and angles, therefor it is a scalene triangle.

It cannot be a right triangke bc there is no right angle, and no obtuse either so that crosses out obtuse as an option as well. In order to be an isoceles triangle it must have two sides of equal length, but it does not.

7 0
3 years ago
Find the solution of the differential equation that satisfies the given initial condition. y' tan x = 3a + y, y(π/3) = 3a, 0 &lt
Paladinen [302]

Answer:

y(x)=4a\sqrt{3}* sin(x)-3a

Step-by-step explanation:

We have a separable equation, first let's rewrite the equation as:

\frac{dy(x)}{dx} =\frac{3a+y}{tan(x)}

But:

\frac{1}{tan(x)} =cot(x)

So:

\frac{dy(x)}{dx} =cot(x)*(3a+y)

Multiplying both sides by dx and dividing both sides by 3a+y:

\frac{dy}{3a+y} =cot(x)dx

Integrating both sides:

\int\ \frac{dy}{3a+y} =\int\cot(x) \, dx

Evaluating the integrals:

log(3a+y)=log(sin(x))+C_1

Where C1 is an arbitrary constant.

Solving for y:

y(x)=-3a+e^{C_1} sin(x)

e^{C_1} =constant

So:

y(x)=C_1*sin(x)-3a

Finally, let's evaluate the initial condition in order to find C1:

y(\frac{\pi}{3} )=3a=C_1*sin(\frac{\pi}{3})-3a\\ 3a=C_1*\frac{\sqrt{3} }{2} -3a

Solving for C1:

C_1=4a\sqrt{3}

Therefore:

y(x)=4a\sqrt{3}* sin(x)-3a

3 0
4 years ago
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