Can someone help and explain and do the solution pls :(

Mathematics

1 answer:

brilliants [131]3 years ago

6 0

Consider ∆JWZ and ∆JKZ

WZ~KJ (given)

/ WZJ~/ KJZ (given)

JZ~JZ (common)

Therefore,

∆JWZ~∆JKZ by SAS congruence rule.

JW~ZK by CPCT.

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