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Free_Kalibri [48]
3 years ago
8

Can someone help and explain and do the solution pls :(

Mathematics
1 answer:
brilliants [131]3 years ago
6 0

Consider ∆JWZ and ∆JKZ

WZ~KJ (given)

<u>/</u><u> </u><u>WZJ</u>~<u>/</u><u> </u>KJZ (given)

JZ~JZ (common)

Therefore,

∆JWZ~∆JKZ by SAS congruence rule.

JW~ZK by CPCT.

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Zepler [3.9K]

Answer:

<h3>consistent independent</h3>

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4 0
3 years ago
Find the opposite of the polynomial.<br> -60^3 - 8a +5
GrogVix [38]

Answer:

60^3 + 8a -5

Step-by-step explanation:

Like opposite of 5 is 5×-1 = -5,

Opposite of -60³ - 8a +5 is:

-(-60³ - 8a +5)

60³ + 8a - 5

3 0
4 years ago
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You have 8 dimes. You trade each dime for 10 pennies. How many pennies will you have?
Salsk061 [2.6K]
You will have 80 pennies
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8×10=80 pennies
8 0
3 years ago
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Do what it says on the image (NO SPAM LINKS!!) ​
Gennadij [26K]

Answer:

The answer is B.

Step-by-step explanation:

Hope this helps!

6 0
2 years ago
Of 560 samples of seafood purchased from various kinds of food stores in different regions of a country and genetically compared
frutty [35]

Answer:

a) (0.5256,0.5944)  

c) Criticism is invalid

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 560

Proportion of mislabeled = 56%

\hat{p} = 0.56

a) 90% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.64

Putting the values, we get:

0.56\pm 1.64(\sqrt{\dfrac{0.56(1-0.56)}{560}}) = 0.56\pm 0.0344\\\\=(0.5256,0.5944)

b) Interpretation of confidence interval:

We are 90% confident that the true proportion of all seafood in the country that is mislabeled or misidentified is between 0.5256 and 0.5944 that is 52.56% and 59.44%.

c) Validity of criticism

Conditions for validity:

np > 10\\n(1-p)>10

Verification:

560\times 0.56 = 313.6>10\\560(1-0.56) = 246.4>10

Both the conditions are satisfied. This, the criticism is invalid.

8 0
4 years ago
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