Question

2/3x+14-3x>-7

Answer 1

Answer:

$\large\boxed{x$

Step-by-step explanation:

$\dfrac{2}{3}x+14-3x>-7\qquad\text{subtract 14 from both sides}\\\\\dfrac{2}{3}x+14-14-3x>-7-14\\\\\dfrac{2}{3}x-3x>-21\qquad\text{multiply both sides by 3}\\\\3\!\!\!\!\diagup^1\cdot\dfrac{2}{3\!\!\!\!\diagup_1}x-(3)(3x)>(3)(-21)\\\\2x-9x>-63\\\\-7x>-63\qquad\text{change the signs}\\\\7x$

Answer 2

Answer:

x < 9

Step-by-step explanation:

$\frac{2}{3} x+14-3x>-7$

First, write 3 as a fraction:

$\frac{2}{3} x+14-\frac{3}{1}x>-7$

The common denominator is 3, so:

$\frac{2}{3} x+14-\frac{9}{3}x>-7$

Combine the fractions:

$\frac{2-9}{3} x+14>-7\\-\frac{7}{3} x+14>-7$

Subtract 14 from both sides:

$-\frac{7}{3} x>-21$

Multiply both sides by 3:

$-7x>-63$

Divide both sides by -7 (don't forget to flip the sign when multiplying or dividing by a negative number):

$x$