You divide 33 by 113 and you get .29 times 9 and you get 2.63
<u>1</u><u>.</u><u> </u><u>(ab + bc) (ab – bc) + (bc + ca) (bc – ca) + (ca + ab) (ca – ab) = 0</u>
We know that (a+b)(a-b) = a²-b²
(ab + bc)(ab -bc) can be written as a²b² - b²c²
(bc + ca)(bc -ca) can be written as b²c² - c²a²
(ca + ab)(ca - ab) can be written as c²a² - a²b²
→ a²b² - b²c² + b²c² - c²a² + c²a² - a²b²
→ a²b² - a²b² - b²c² + b²c² - c²a² + c²a²
→ 0
<u>2</u><u>.</u><u> </u><u>(a + b + c) (a² + b² + c² – ab – bc – ca) = a³ + b³+ c³ – 3abc</u>
→ a³ + ab² + ac² -a²b - abc -ca² + a²b + b³ + bc² - ab² - b²c - abc + a²c + b²c + c³ - abc - bc² - c²a
→ a³ + b³+ c³ + (- abc - abc - abc) + (ab² - ab² )+ (ac² - ca² ) -(a²b + a²b )+ (bc² - bc² )+ (a²c - c²a) + (b²c - b²c)
→ a³+b³+c³ - 3 abc .
<u>3</u><u>.</u><u> </u><u>(p – q) (p² + pq + q²) = p³ – q³. </u>
→ p³ + p²q + pq² - p²q - pq² - q³
→ p³ - q³ +(p²q - p²q) + (pq² - pq²)
→ p³ - q³
Answer:
Step-by-step explanation:
3x + y = 7
-2x - y = 9
x = 16
answer is B
3(16) + y = 7
48 + y = 7
y = -41
The first option, as it positively supports the claim stated.
Answer:
A Rhombus
Step-by-step explanation:
it's a quadrilateral, but its sides aren't congruent
