Given that Erica and AAron,are using lottery system to decide who will wash dishes every night.
They put some red and blue power chips and draw each one. If same colour, Aaron will wash and if not same colours Erica will wash
If the game is to be fair, then both should have equal chances of opportunity for washing.
i.e. Probability for Erica washing = Prob of Aaron washing
i.e. P(different chips) = P(same colour chips)
Say there are m red colours and n blue colours.
Both are drawing at the same time.
Hence Prob (getting same colour) = (mC2+nC2)/(m+n)C2
Probfor different colour = mC1+nC1/(m+n)C2
The two would be equal is mC2 +nC2 = m+n
This is possible if mC2 =m and nC2 = n.
Or m = 2+1 =3 and n =3
That for a fair game we must have both colours to be 3.
Answer:
36in²
Step-by-step explanation:
<h3>Area of the White Region: </h3>
A = l * w
The rectangle is 3 by 2.
A = 3 * 2
A = 6
The white part of the rectangle is 6in².
<h3>Area of the blue region:</h3>
A = l * w
The rectangle is 6 by 7.
A = 6*7
A = 42
The blue part of the rectangle is 42in².
<h3>Area of the shaded region:</h3>
[area of the blue part] - [area of the white part]
42 - 6 = 36
The area of the shaded region should be 36in².
Answer: Can you translate for me? I don't know spanish.
Step-by-step explanation:
:)
