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3 years ago

10 points worth please help!

Mathematics

2 answers:

Firdavs [7]3 years ago

8 0

I’ve attached my work...
Hope it helps!
Your answer is 20

Shkiper50 [21]3 years ago

6 0

You need 20 teaspoons of red paint

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The first term of a geometric sequence is −2 and the common ratio is 3. What is the fourth term of the sequence?

Nat2105 [25]

Answer: -54

Step-by-step explanation:

The question is the first term of a geometric sequence is −2 and the common ratio is 3. The formula for finding the nth term of a geometric sequence is: ar^n-1

where,

a = first term = -2

r = common ratio = 3

n = number of terms = 4

The solution has been attached. The answer is -54

5 0

3 years ago

A corner store sells two kinds of baked goods: cakes and pies. A cake costs $4 and a pie costs $6. In one day, the store sold 9

Troyanec [42]

Answer:

the number of cakes sell is 5

Step-by-step explanation:

The computation of the number of cakes sold is shown below;

Let us assume

The cake be C

And, the pie cost be P

Given that

There is two types of baked goods sold

The cost of the cake is $4

And, the cost of the pie cost is $64

Now the store sold 9 baked goods for a total of $44

So, the equation would be

C + P = 9

P = 9 - C ...... (1)

4C + 6P = 44............(2)

Now put the value of P in equation 2

4C + 6(9 - C) = 44

4C + 54 - 6C = 44

-2C = -10

C = 5

And, P = 4

hence, the number of cakes sell is 5

8 0

3 years ago

Please help me with this problem!!!

Lilit [14]

$3 {}^{4x - 5} = ( \frac{1}{27} ) {}^{2x + 10} \\ note \: \: that = \\ ( \frac{1}{27} ) = ( \frac{1}{3 {}^{3} } ) = 3 {}^{ - 3} \\ \\ 3 {}^{4x - 5} = (3 {}^{ - 3} ) {}^{2x + 10} \\ 3 {}^{4x + 5} = 3 {}^{ - 3(2x + 10)} \\ equal \: \: bases = > equal \: exponents$

$4x - 5 = - 3(2x + 10) \\ 4x - 5 = - 6x - 30 \\ 4x + 6x = - 30 + 5 \\ 10x = - 25 \\ x = - 2.5$

7 0

2 years ago

Read 2 more answers

What is the value of m in the figure below in this diagram abd bcd

oee [108]

$\triangle BCA\ \text{and}\ \triangle DCB\ \text{are similar (AAA). Therefore the sides are in proportion:}\\\\\dfrac{BC}{CD}=\dfrac{AC}{BC}\\\\\text{We have}\\\\BC=m\\CD=7\\AC=7+11=18\\\\\text{Substitute:}\\\\\dfrac{m}{7}=\dfrac{18}{m}\qquad\text{cross multiply}\\\\m^2=(7)(18)\\\\m^2=126\to\boxed{m=\sqrt{126}}\to\boxed{A.}$

6 0

3 years ago

Click on the graph below to create a quadrilateral with vertices at the following points. (-4,9), (-8,9), (-9,7), (-9, 4)

Shalnov [3]

Given (-4,9) (-8,9),(-9,7,(-9,4)

...

To Find : plot the point and draw quadrilateral

Solution:

(-4,9)

go 4 left of origin and then go 9 up

(-8,9)

go 8 left of origin and then go 8 up

(-9,7)

go 9 left of origin and then go 7 up

(-9,4)

go 9 left of origin and then go join (-4,9) with (-8,9) and (-9,4) 4 up

join (-9,7) with (-8,9) and (-9,4)

Quadrilateral is constructed

4 0

2 years ago