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2 years ago

Need help 8387.02 + 744.8

Mathematics

2 answers:

vivado [14]2 years ago

5 0

The answer would be <span>9131.82</span>

True [87]2 years ago

3 0

9131.82 is the answer to the question

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If f(x)=3x-2 find f-1 (13)

SOVA2 [1]

Answer:

Firstly

f(x)=3x-2=y then

Interchanging x and y we get

x=3y-2

x+2=3y

y=(x+2)/3

f-1(x)=(x+2)/3

f-1(13)=(13+2)/3

f-1(13)=5

3 0

3 years ago

Use math vocabulary to explain why you think this number does not belong in the group. Be sure to write in complete sentences.

NISA [10]

Answer:

because like for example the given number are 01 12

23 34

or 12233445566778 and etc.

your situation are 4556 and 3224 because are not ordered pair

8 0

2 years ago

2. Check the boxes for the following sets that are closed under the given

son4ous [18]

The properties of the mathematical sequence allow us to find that the recurrence term is 1 and the operation for each sequence is

a) Subtraction

b) Addition

c) AdditionSum

d) in this case we have two possibilities

* If we move to the right the addition

* If we move to the left the subtraction

The sequence is a set of elements arranged one after another related by some mathematical relationship. The elements of the sequence are called terms.

The sequences shown can be defined by recurrence relations.

Let's analyze each sequence shown, the ellipsis indicates where the sequence advances.

a) ... -7, -6, -5, -4, -3

We can observe that each term has a difference of one unit; if we subtract 1 from the term to the right, we obtain the following term

-3 -1 = -4

-4 -1 = -5

-7 -1 = -8

Therefore the mathematical operation is the subtraction.

b) $0. \sqrt{1}. \sqrt{4}, \sqrt{9}, \sqrt{16}, \sqrt{25}$ ...

In this case we can see more clearly the sequence when writing in this way

$0, \sqrt{1^2}. \sqrt{2^2}, \sqrt{3^2 } . \sqrt{4^2} , \sqrt{5^2}$

each term is found by adding 1 to the current term,

$\sqrt{(0+1)^2} = \sqrt{1^2} \\\sqrt{(1+1)^2} = \sqrt{2^2}\\\sqrt{(2+1)^2} = \sqrt{3^2}\\\sqrt{(5+1)^2} = \sqrt{6^2}$

Therefore the mathematical operation is the addition

c) $... \frac{-10}{2}. \frac{-8}{2}, \frac{-6}{2}, \frac{-4}{2}. \frac{-2}{2}. ...$

The recurrence term is unity, with the fact that the sequence extends to the right and to the left the operation is

To move to the right add 1

- $\frac{-10}{2} + 1 = \frac{-10}{2} - \frac{2}{2} = \frac{-8}{2}\\\frac{-8}{2} + \frac{2}{2} = \frac{-6}{2}$

To move left subtract 1

$\frac{-2}{2} - 1 = \frac{-4}{2}\\\frac{-4}{2} - \frac{2}{2} = \frac{-6}{2}$

Using the properties the mathematical sequence we find that the recurrence term is 1 and the operation for each sequence is

a) Subtraction

b) Sum

c) Sum

d) This case we have two possibilities

If we move to the right the sum

If we move to the left we subtract

Learn more here: brainly.com/question/4626313

5 0

2 years ago

A company introduces a new product for which the number of units sold S is

KonstantinChe [14]

(a) The "average value" of a function over an interval [a,b] is defined to be

(1/(b-a)) times the integral of f from the limits x= a to x = b.

Now S = 200(5 - 9/(2+t))

The average value of S during the first year (from t = 0 months to t = 12 months) is then:

(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12

or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12

This equals 200/12 * (5t -9ln(2+t))

Evaluating this with the limits t= 0 to t = 12 gives:

708.113 units., which is the average value of S(t) during the first year.

(b). We need to find S'(t), and then equate this with the average value.

Now S'(t) = 1800/(t+2)^2

So you're left with solving 1800/(t+2)^2 = 708.113

<span>I'll leave that to you</span>

6 0

2 years ago

Which ratio will help to find the value of the missing side of the triangle?

kari74 [83]

Answer:

Correct ratio is:

2/3 = x/4

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers