Factor out the 4 in both equations
8a^2-20^2=(2^2 times a^2 times 2)-(2^2 times 5)
therefor it is also equal to
(2a)^2 times 2-(2^2 times 5)
we can force it into a difference of 2 perfect squares which is a^2-b^2=(a-b)(a+b)
(2a√2)^2-(2√5)^2=((2a√2)-(2√5))((2a√2)+(2√5))
I guess you mean that the zeroes are 2 and -3/5.
In factor form the function could be
f(x) = (x - 2)(3x + 5)
expanding we get
f(x) = 3x^2 -x - 10
I assume you mean one that is not rational, such as √2. In such a case, you make a reasonable estimate of it's position, and then label the point that you plot.
For example, you know that √2 is greater than 1 and less than 2, so put the point at about 1½ (actual value is about 1.4142).
For √3, you know the answer is still less than 4, but greater than √2. If both of those points are required to be plotted just make sure you put it in proper relation, otherwise about 1¾ is plenty good (actual value is about 1.7321).
If you are going to get into larger numbers, it's not a bad idea to just learn a few roots. Certainly 2, 3, and 5 (2.2361) and 10 (3.1623) shouldn't be too hard.
Then for a number like 20, which you can quickly workout is √4•√5 or 2√5, you could easily guess about 4½ (4.4721).
They're usually not really interested in your graphing skills on this sort of exercise. They just want you to demonstrate that you have a grasp of the magnitude of irrational numbers.
Answer:
X = 13.13 feet
Step-by-step explanation:
Let the distance between Lila and Mark be x.
Let the distance between Avery and lila be A= 20
Let the distance between Avery and Mark be B= 30
Angle x = 200-180=20°
To solve this question we will use the cosine formula which is
X² = A²+ B² -2ABcosx
X²= 20² + 30² -2(20)(30)cos20
X²=1300-1127.6
X²= 172.4
X= 13.13
