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3 years ago

-12 x (1/3)? what is this equal to!

Mathematics

2 answers:

marishachu [46]3 years ago

8 0

Answer:

-4

Step-by-step explanation:

-12 times 1/3.

It's pretty much just -12x1, then divided by 3.

-12x1 is equal to -12.

Your equation is now simplified, making it easier to solve.

Your equation is: $\frac{-12}{3}$

-12 divided by 3 is -4, because when a negative number is divided (or multiplied) by a positive number, the quotient (or product) is negative.

-12 x (1/3) = -12/3 = -4.

Strike441 [17]3 years ago

6 0

Answer:

-4

Step-by-step explanation:

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TanB=CA/AB
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3 years ago

Describe the transformation's necessary to transform the graph f(x) into that of g(x)

slamgirl [31]

Answer:

C and F

Step-by-step explanation:

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3 years ago

A weight lifter can deadlift 275 pounds. She can increase the weight that she can lift according to the function W(x)=275(1.05)^

suter [353]

Answer:

$350.98\ pounds$

Step-by-step explanation:

we have

$W(x)=275(1.05^{x})$

where

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x is the number of training cycles completed

For $x=5\ cycles$

substitute the value of x in the function

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4 years ago

This year, a small business had a total revenue of $40,700. If this is 26% less than their total revenue the previous year, what

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8 0

2 years ago

Marcy has 150 to buy packages of hotdogs and hamburgers for her booth at the carnival. Grocery store she found packages of hotdo

bekas [8.4K]

Answer:

Part (A): The required equation will be: $6d+20b=150$

Part (B):The required equation will be: $d=\frac{150-20b}{6}$

Part (C):The required equation will be: $b=\frac{150-6d}{20}$

Step-by-step explanation:

Consider the provided information.

Let d represents number of packages of hot dogs and b represents the number of packages of hamburgers.

Part (a)

It is given that the cost of a package of hot dogs is $6 and cost of a package of hamburger is $20.

The required equation will be: $6d+20b=150$

Part (b) Solve the above equation for d.

Subtract 20b from both sides.

$6d=150-20b$

Divide 6 from both sides.

$d=\frac{150-20b}{6}$

The required equation will be: $d=\frac{150-20b}{6}$

Part (c) Solve the equation for b.

Subtract 6d from both sides.

$20b=150-6d$

Divide 20 from both sides, we get

$b=\frac{150-6d}{20}$

The required equation will be: $b=\frac{150-6d}{20}$

6 0

3 years ago