The value at the end of the year is 100% - 20% = 0.80 of the value at the beginning of the year. After 4 years of multiplying by this factor, the value is
$17,500·0.80⁴ = $7,168
We can plug those values into the equation, and if the answer is incorrect, we'll know if either one is extraneous.
√11 - 2(-7) = √(-7)^2 + 4(-7) + 4
√25 = √25
5 = 5
The first solution, -7, makes the equation true, and so it is not extraneous.
√11 - 2(1) = √(1)^2 + 4(1) + 4
√9 = √9
3 = 3
The second solution, 1, makes the equation true, and so it is also not extraneous.
<h3>The correct option is D, neither solution is extraneous. </h3>
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define</u>
<u />
<u />
<u />
<u>Step 2: Solve for </u><em><u>x</u></em>
- Cross-multiply:

- Distribute:

- Isolate <em>x</em> terms:

- Isolate <em>x</em> term:

- Isolate <em>x</em>:

- Rewrite:

Answer:
512 student tickets.
Step-by-step explanation:
Let x be number of student tickets and y be number of adult tickets.
We have been given that at Friday's football game 1,294 tickets were sold. We can represent this information as:

We are also told that each student ticket costs $5.00, and each adult ticket costs $8.00 and 1,294 tickets were sold for a total amount of $8,816. We can represent this information as:
From equation (1) we will get,
Substituting this value in equation (2) we will get,






Therefore, 512 student tickets were purchased at Fridays football game.