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IrinaK [193]
3 years ago
11

Plz, help me with this question!

Mathematics
1 answer:
Leto [7]3 years ago
3 0

Answer:

870

Step-by-step explanation:

Assuming you mean

30P_{2}

Using the definition

nP_{r} = \frac{n!}{(n-r)!}

where n! = n(n - 1)(n - 2) ..... 3 × 2 × 1

Then

30P_{2} = \frac{30!}{28!} = \frac{30(29)(28)(27)...}{28(27)(26).....}

Cancel the terms 28(27)... on numerator/ denominator, leaving

30P_{2} = 30 × 29 = 870

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