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3 years ago

Use trial and improvement to find the solution to this positive equation

Mathematics

1 answer:

Novay_Z [31]3 years ago

8 0

It's 3.01 sorry wrong question please forgive me

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Atul deposited 30% of his income in a bank. After spending 50% of the remaining ,he had ripped 10,500 left with

Alex Ar [27]

Answer:

30,000

Step-by-step explanation:

50% remaining = 10500

After deposit: 2×10500 = 21000

210000 : 70%

X : 100%

21000/70 = X/100

X = 30,000

6 0

3 years ago

Read 2 more answers

Please helpppppppppp

Alika [10]

Answer:

x = 1/3

Step-by-step explanation:

f(x) = -3x^2 + 2x-17

This is in the form

ax^2 +bx+c

a = -3 b = 2 c = -17

The axis of symmetry is at

x = -b/2a

x = -2/ (2*-3)

x = -2/-6

x = 1/3

8 0

3 years ago

You have two exponential functions. One function has the formula g(x) = 5 x . The other function has the formula h(x) = 5-x . Wh

Marrrta [24]

Hmm it would be k(x)=2(5x) or it could be k(x)=10x

Hope this helps!

5 0

3 years ago

Read 2 more answers

Wo runners are saving money to attend a marathon. The first runner has $112 in savings, received a $45 gift from a friend, and w

SpyIntel [72]

Answer:

I believe the last answer is correct

Step-by-step explanation:

Both runners are gaining money

8 0

3 years ago

Find an equation of the line in the form ax+by=c whose x-intercept is 12 and y-intercept is 4, where a, b, and c are integer

Lostsunrise [7]

Answer:

The equation of the line in $ax+by=c$ form where $a,b,c$ are integers with no factor common to all three, and greater than or equal 0 is:

$x+3y=12$

Step-by-step explanation:

Given:

x-intercept = 12

y-intercept = 4

To find the equation of line in the form $ax+by=c$ where $a,b,c$ are integers with no factor common to all three, and greater than or equal 0.

Solution:

The x-intercept is the point at which the line cuts the x-axis. The point of x-intercept is given as $(x,0)$

Thus, on point of the line is (12,0)

The y-intercept is the point at which the line cuts the y-axis. The point of y-intercept is given as $(0,y)$ .

Thus, on point of the line is (0,4)

Using the two points we can find the slope of the line using the slope formula.

$m=\frac{y_2-y_1}{x_2-x_1}$

So, slope of the line can b given as:

$m=\frac{4-0}{0-12}$

$m=\frac{4}{-12}$

$m=-\frac{1}{3}$

The slope intercept form of the equation of he line is given as:

$y=mx+b$

where $m$ represents slope of the line and $b$ represents the y-intercept.

So, the equation of the line can be given as:

$y=-\frac{1}{3}x+4$

Multiplying each term by 3 to remove fraction.

$3y=3.-\frac{1}{3}x+4(3)$

$3y=-x+12$

Adding $x$ both sides.

$3y+x=-x+x+12$

$3y+x=12$

Thus, the equation of the line in $ax+by=c$ form where $a,b,c$ are integers with no factor common to all three, and greater than or equal 0 is:

$x+3y=12$

8 0

3 years ago