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Brrunno [24]
3 years ago
7

alt=" \sqrt{4. \sqrt{9} } " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
kozerog [31]3 years ago
5 0

Answer:

2 \sqrt{3}

Step-by-step explanation:

1) Since 3 × 3 is 9, the square root of 9 is 3.

\sqrt{4 \times 3}

2) Simplify 4 × 3 to 12.

\sqrt{12}

3) Simplify

\sqrt{12}  \:  \: to \: 2 \sqrt{3}

2 \sqrt{3}

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Answer:

I'm not sure but you can try to snap a pic next time for better answer

Step-by-step explanation:

I'm not sure what you mean

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Heyyy Friends!! Whats 9+(1*1)+6=??
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Answer:

16 :)

Step-by-step explanation:

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3 years ago
The average yield of the standard variety off soybeans per acre on a farm in a region is 48.8 bushels per acre, with a standard
I am Lyosha [343]

Answer:

z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3  

p_v =P(Z>2.3)=1-P(Z  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.  

Step-by-step explanation:

1) Data given and notation  

\bar X=53.4 represent the sample mean

\sigma=12 represent the population standard deviation assumed

n=36 sample size  

\mu_o =48.8 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is higher than 48.8, the system of hypothesis would be:  

Null hypothesis:\mu \leq 48  

Alternative hypothesis:\mu > 48  

Since we assume that know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3  

4)P-value  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.3)=1-P(Z  

5) Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.  

3 0
4 years ago
The graph below shows the number of new clients brought into Sunnydays Insurance Company. Why is the graph misleading?
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The graph is misleading because the year’s interval is not constant. The first year to the second year, the gap is 1 year; in the second to the third year, the gap is 2; in the third to the fourth year is 4; and the fourth to the fifth year is 6.

8 0
4 years ago
What is the probability that a student writes chicken
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Answer:

Chicken

Step-by-step explanation: 7829219882 / 278892828891271289289

depends on the situation like this one at times :)

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