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3 years ago

How much do I shade in

Mathematics

2 answers:

zheka24 [161]3 years ago

6 0

the answer is 2/5. You just cancle 2 and 4

lara [203]3 years ago

3 0

4/10 is equal to 4 out of 10 or 40%
This means you should shade 4 of the 10 blocks

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An artist uses different types of paper to create her masterpieces. She has shiny metallic paper and pink glittery paper. The sh

Naya [18.7K]

Answer:

it is 24 . Logically in my idea .

4 0

3 years ago

What is the hight of a Building 1 Angle 71o Distance 20 meters

vlabodo [156]

The height of a building is 58.08 meters if the angle is 71 degree and the distance between A and B is 20 meters.

<h3>What is trigonometry?</h3>

Trigonometry is a branch of mathematics that deals with the relationship between sides and angles of a right-angle triangle.

We have:

Angle = 71 degree

Distance between A and B = 20 meters

Let's suppose the height of the building is x meters.

From the right angle triangle applying the tan ratio:

tan71 = x/20

x = 58.08 meter

Thus, the height of a building is 58.08 meters if the angle is 71 degree and the distance between A and B is 20 meters.

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2 years ago

Is 0.843 less than 0.846

ioda

Answer:

0.003

Step-by-step explanation:

6-3 =3 and 4-4 = is 0 and 8-8= 0 so the answer is 0.003

5 0

3 years ago

Read 2 more answers

Dexter has four different coins in his pocket. He randomly selects a coin from his pocket, replaces it, and selects another coin

skad [1K]

Answer:

Step-by-step explanation:

So what is the probability of the selecting the first coin? There are total of 4 different coins, so the probability of getting a dime is 1 out of 4, then he replace it, then again the probability stays the same, he still has 1 out 4 chance of getting a dime. So then it's just 1/4*1/4=1/16 :)

4 0

3 years ago

Evaluate the interval (Calculus 2)

Darya [45]

Answer:

$2 \tan (6x)+2 \sec (6x)+\text{C}$

Step-by-step explanation:

<u>Fundamental Theorem of Calculus</u>

$\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))$

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given indefinite integral:

$\displaystyle \int \dfrac{12}{1-\sin (6x)}\:\:\text{d}x$

$\boxed{\begin{minipage}{5 cm}\underline{Terms multiplied by constants}\\\\$\displaystyle \int a\:\text{f}(x)\:\text{d}x=a \int \text{f}(x) \:\text{d}x$\end{minipage}}$

If the terms are multiplied by constants, take them outside the integral:

$\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)}\:\:\text{d}x$

Multiply by the conjugate of 1 - sin(6x) :

$\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)} \cdot \dfrac{1+\sin(6x)}{1+\sin(6x)}\:\:\text{d}x$

$\implies 12\displaystyle \int \dfrac{1+\sin(6x)}{1-\sin^2(6x)} \:\:\text{d}x$

$\textsf{Use the identity} \quad \sin^2 x+ \cos^2 x=1:$

$\implies \sin^2 (6x) + \cos^2 (6x)=1$

$\implies \cos^2 (6x)=1- \sin^2 (6x)$

$\implies 12\displaystyle \int \dfrac{1+\sin(6x)}{\cos^2(6x)} \:\:\text{d}x$

Expand:

$\implies 12\displaystyle \int \dfrac{1}{\cos^2(6x)}+\dfrac{\sin(6x)}{\cos^2(6x)} \:\:\text{d}x$

$\textsf{Use the identities }\:\: \sec \theta=\dfrac{1}{\cos \theta} \textsf{ and } \tan\theta=\dfrac{\sin \theta}{\cos \theta}:$

$\implies 12\displaystyle \int \sec^2(6x)+\dfrac{\tan(6x)}{\cos(6x)} \:\:\text{d}x$

$\implies 12\displaystyle \int \sec^2(6x)+\tan(6x)\sec(6x) \:\:\text{d}x$

$\boxed{\begin{minipage}{5 cm}\underline{Integrating $\sec^2 kx$}\\\\$\displaystyle \int \sec^2 kx\:\text{d}x=\dfrac{1}{k} \tan kx\:\:(+\text{C})$\end{minipage}}$

$\boxed{\begin{minipage}{6 cm}\underline{Integrating $ \sec kx \tan kx$}\\\\$\displaystyle \int \sec kx \tan kx\:\text{d}x= \dfrac{1}{k}\sec kx\:\:(+\text{C})$\end{minipage}}$

$\implies 12 \left[\dfrac{1}{6} \tan (6x)+\dfrac{1}{6} \sec (6x) \right]+\text{C}$

Simplify:

$\implies \dfrac{12}{6} \tan (6x)+\dfrac{12}{6} \sec (6x)+\text{C}$

$\implies 2 \tan (6x)+2 \sec (6x)+\text{C}$

Learn more about indefinite integration here:

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3 0

2 years ago