Answer:
![a)\ \ \bar x_m-\bar x_f=67.03\\\\b)\ \ E=15.7416\\\\c)\ \ CI=[51.2884, \ 82.7716]](https://tex.z-dn.net/?f=a%29%5C%20%5C%20%5Cbar%20x_m-%5Cbar%20x_f%3D67.03%5C%5C%5C%5Cb%29%5C%20%5C%20E%3D15.7416%5C%5C%5C%5Cc%29%5C%20%5C%20CI%3D%5B51.2884%2C%20%5C%2082.7716%5D)
Step-by-step explanation:
a. -Given that:
#The point estimator of the difference between the population mean expenditure for males and the population mean expenditure for females is calculated as:
Hence, the pointer is estimator 67.03
b. The standard error of the point estimator,
is calculated by the following following:
-And the margin of error, E at a 99% confidence can be calculated as:
Hence, the margin of error is 15.7416
c. The estimator confidence interval is calculated using the following formula:
#We substitute to solve for the confidence interval using the standard deviation and sample size values in a above:
![CI=\bar x_m-\bar x_f\ \pm z_{\alpha/2}\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}\\\\=(135.67-68.64)\pm 15.7416\\\\=67.03\pm 15.7416\\\\=[51.2884, \ 82.7716]](https://tex.z-dn.net/?f=CI%3D%5Cbar%20x_m-%5Cbar%20x_f%5C%20%5Cpm%20z_%7B%5Calpha%2F2%7D%5Csqrt%7B%5Cfrac%7B%5Csigma_m%5E2%7D%7Bn_m%7D%2B%5Cfrac%7B%5Csigma_f%5E2%7D%7Bn_f%7D%7D%5C%5C%5C%5C%3D%28135.67-68.64%29%5Cpm%2015.7416%5C%5C%5C%5C%3D67.03%5Cpm%2015.7416%5C%5C%5C%5C%3D%5B51.2884%2C%20%5C%2082.7716%5D)
Hence, the 99% confidence interval is [51.2884,82.7716]
Shaded is 8.67
Circle A= pir^2
A= 3.14(4)(4)
A= 50.24
Hexagon
A= 1/2ap
1/2(4)(2sqrtof3)(6)
A= 41.569
50.24-41.569=8.671
Answer:
The variable d stands for how many calories she used.
Step-by-step explanation:
the problem says that she uses 1 calorie per minute while walking, and then it says that she walked 12 minutes. 12×1= 12 calories
d=12 calories which equals to the 12 minutes she walked
Answer:
2 days!
Step-by-step explanation:
So, we have 50 + 35x = 70 + 25x.
Solving, we obtain 10x = 20, so x = 2.
Your answer is 2 days.
If this answer helped you, please tell me! :)
Answer:
parabolas (quadratic curves)
in the real world -
any trajectory of any item that is thrown on earth can be represented as a quadratic equation.
I do not know what you mean by the mathematical process.
Step-by-step explanation:
