Y=kx+b
2k+b=-1
6k+b=1
6k+b-2k-b=2
4k=2
k=1/2
b=-2
y=1/2x-2
So your answer is option A
Step-by-step explanation:
The function is as follows :

We need to find the zeroes of the function in the simplest radical form.The zero of the above function is given by :

Here,
b = 5
a = 1
c = 5
So,

Hence, the correct option is (c).
Answer:
255290.4Aacdn
Step-by-step explanation:
10A*2.7*8*223andc*5.3
Answer:
f(t) = 15 + 160 + 1
Step-by-step explanation:
it said that t= 4 and because the t is after the 40 you would times 40 by 4 to get 160. Then you add them all up and there you go you got your velocity and speed.
Answer:
Follows are the responses to the given question:
Step-by-step explanation:
Please find the complete question in the attached file.



The stem & leaf show demonstrates that 0.55 for both the data is indeed a reasonable value.
The probable outlier is the data value 0.76.
The variability of the techniques is relatively large.
It show isn't symmetrical and seems to be optimistic.