Answer:
The probability that the average score of the 49 golfers exceeded 62 is 0.3897
Step-by-step explanation:
The average score of all golfers for a particular course has a mean of 61 and a standard deviation of 3.5


We are supposed to find he probability that the average score of the 49 golfers exceeded 62.
Formula : 


Refer the z table for p value
p value = 0.6103
P(x>62)=1-P(x<62)=1-0.6103=0.3897
Hence the probability that the average score of the 49 golfers exceeded 62 is 0.3897
Given that the US population is approximately 308,000,000 in 2010 and that 6.5% of this population is under 5 years of age, we will know that number of children by multiplying 6.5% by 308,000,000. So the answer would be 20,020,000. So that is the number of children below 5 years old. Hope this helps.
6 pies.
If 8 teachers finish one whole pie, and they need to feed 47, then they need 6 pies with 8 slices each aka 48 slices total, there will be one slice leftover for the principal :D
Answer:
p = 
Step-by-step explanation:
Given that p varies inversely with q then the equation relating them is
p =
← k is the constant of variation
To find k use the condition p = 2 when q = 1, thus
k = pq = 2 × 1 = 2
p =
← equation of variation
Can you tell us what the expression is in the question?