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3 years ago

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Calculate the value of x for the equation 7x +3+2= 26. A. 2 B. 3 C. -3 D. 21

2 answers:

Nookie1986 [14]3 years ago

8 0

The answer is B because 26-2 is 24 and 24-3 is 21 and 21/7 is 3 therefore x=3

Usimov [2.4K]3 years ago

8 0

Answer:

3

Step-by-step explanation:

<em>here's</em><em> your</em><em> solution</em>

<em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>7</em><em>x</em><em> </em><em>+</em><em> </em><em>3</em><em> </em><em>+</em><em> </em><em>2</em><em> </em><em>=</em><em> </em><em>2</em><em>6</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>7</em><em>x</em><em> </em><em>+</em><em> </em><em>5</em><em> </em><em>=</em><em>2</em><em>6</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>7</em><em>x</em><em> </em><em>=</em><em> </em><em>2</em><em>6</em><em> </em><em>-</em><em> </em><em>5</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>7</em><em>x</em><em> </em><em>=</em><em> </em><em>2</em><em>1</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>X </em><em>=</em><em> </em><em>2</em><em>1</em><em>/</em><em>7</em>

<em> </em><em> </em><em> </em><em> </em><em> </em>

=> x = 3

hope it helps

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Does a rectangle have four congruent sides?

ololo11 [35]

Answer:

NO.

Step-by-step explanation:

In geometry, two figures or objects are congruent if they have the same shape and size, or if one has the same shape and size as the mirror image of the other. So, in other words, 2 shapes or figures in geometry are congruent if they have the exact same size and shape.

A rectangle has 2 pairs of parallel sides. One pair is longer than the other pair. Therefore, to be congruent, all sides have to be equal, which is a square, not a rectangle. So the answer is NO.

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3 years ago

If f(x) = x2 - 2x and g(x) = 6x + 4 for which value of x does (t +g)(x)=0

Vinil7 [7]

Answer:

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Assumption:

Find the value of x such that $(f+g)(x)=0$ .

Step-by-step explanation:

$(f+g)(x)=0$

$f(x)+g(x)=0$

$(x^2-2x)+(6x+4)=0$

Combine like terms:

$x^2+4x+4=0$

This is not too bad too factor on the left hand side since 2(2)=4 and 2+2=4.

$(x+2)(x+2)=0$

$(x+2)^2=0$

So we need to solve:

$x+2=0$

Subtract 2 on both sides:

$x=-2$

Let's check:

$(f+g)(-2)$

$f(-2)+g(-2)$

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$(8)+(-8)$

$0$

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