Answer:
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more ponits not fair
Step-by-step explanation:
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Answer:
probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3
Step-by-step explanation:
First of all;
Let B1 be the event that the card with two red sides is selected
Let B2 be the event that the
card with two black sides is selected
Let B3 be the event that the card with one red side and one black side is
selected
Let A be the event that the upper side of the selected card (when put down on the ground)
is red.
Now, from the question;
P(B3) = ⅓
P(A|B3) = ½
P(B1) = ⅓
P(A|B1) = 1
P(B2) = ⅓
P(A|B2)) = 0
(P(B3) = ⅓
P(A|B3) = ½
Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;
P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]
Thus;
P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]
P(B3|A) = (1/6)/(⅓ + 0 + 1/6)
P(B3|A) = (1/6)/(1/2)
P(B3|A) = 1/3
Answer:
1) Amy can invite 17 people.
2) x > 76
3) 40 - 6 is greater than or equal to 3x
4) x is greater than or equal to 98
Step-by-step explanation:
1) 50 + 8x = 200
2) 200 < 3x - 28
3) 40 = 6 +3x
4) (95 + 78 + 89 + x)/4 is greater than or equal to 90
Answer:
2
Step-by-step explanation:
f(x)=2x^2+9x-5
When we are find how many times it intersects the x axis, we are finding the zero's. Set the equation equal to zero
0=2x^2+9x-5
Factor the equation
0 = (2x+1) (x-5)
2*1
1*-5 = -5
2*-5 +1*1 = -9
This checks for the first last and middle terms so we factored correctly
Then using the zero product property
2x+1 = 0 and x-5 =0
2x = -1 x=5
x = -1/2 and x=5
This function crosses the x axis 2 times
Answer:-7x(to the power of 2)-3y+4x-2y(to the 3rd power)-7x( to the third power)
Step-by-step explanation:
Collect like terms