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Alexxx [7]
2 years ago
5

If 5-3(2a+1)=-4+10, what is the value of a+2​

Mathematics
2 answers:
givi [52]2 years ago
7 0

\\ \rm\Rrightarrow 5-3(2a+1)=-4+10

\\ \rm\Rrightarrow 5-6a-3=6

\\ \rm\Rrightarrow -6a+2=6

\\ \rm\Rrightarrow -6a=6-2

\\ \rm\Rrightarrow -6a=4

\\ \rm\Rrightarrow a=\dfrac{4}{-6}

\\ \rm\Rrightarrow a=\dfrac{2}{-3}

Now

\\ \rm\Rrightarrow a+2

\\ \rm\Rrightarrow \dfrac{2}{-3}+2

\\ \rm\Rrightarrow \dfrac{2-6}{-3}

\\ \rm\Rrightarrow \dfrac{-4}{-3}

\\ \rm\Rrightarrow \dfrac{4}{3}

Zepler [3.9K]2 years ago
4 0

Answer:

7/3

Step-by-step explanation:

5 - 3(2a+1) = -4 + 10

=> 5 - 6a + 3 = 6

=> 5 - 6 + 3 = 6a

=> 2 = 6a

=> 6a = 2

=> a = 2/6

=> a = 1/3

a + 2

1/3 + 2

=> 1/3 + 6/3

=> 7/3

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Frank chooses a box at random. If boxes 1 and 3 are chosen, Frank extracts 2 balls without replacement. If box 2 is chosen Frank
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Complete question:

Consider 3 boxes, each of which contains 4 balls in particular, box 1 contains 4 white balls, box 2 contains 3 white balls and 1 red ball, box 3 contains 2 white balls and 2 red balls. Frank chooses a box at random. If boxes 1 and 3 are chosen, Frank extracts 2 balls without replacement. If box 2 is chosen Frank extracts 2 balls with replacement. USE ONLY THE CONDITIONAL PROBABILITY FORMALISM and derive an expression for the probability that the 2 extracted balls are red.

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Step-by-step explanation:

We are given:

Box 1: ( 4White, ORed)

Box 2: (3White, 1Red)

Box 3: (2White, 2 Red)

We are told that if Frank choose from Box 1 and Box 3, 2 balls are extracted without replacement.

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Our Event, E = getting 2 red balls.

Now Box 1 is ruled out, we have:

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Therefore probability that 2 balls extracted are red, we have:

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= 11/288

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3 years ago
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