Answer:
log(x^7·y^2)
Step-by-step explanation:
The applicable rules are ...
... log(a^b) = b·log(a)
... log(ab) = log(a) +log(b)
_____
The first term, 7log(x) can be rewritten as log(x^7). Note that an exponentiation operator is needed when this is written as text.
The second term 2log(y) can be rewritten as log(y^2). These two rewrites make use of the first rule above.
Now, you have the sum ...
... log(x^7) +log(y^2)
The second rule tells you this can be rewritten as ...
... log(x^7·y^2) . . . . . seems to match the intent of the 3rd selection
Answer:
x=17
Step-by-step explanation:
ok so since lines PR and RQ are congruent (we know because of the lines on them), that means angles P and Q are also equal.
now we can set up the equation to find x like this:
29+29+(8x-14)=180 (180 because the three angles of a triangle always equal 180)
x=17
Answer: sorry its not big enough to see sorry
Step-by-step explanation:
To answer your question, this could be the possible answer and i hope you understand and interpret it correctly:
<span>[Integrate [0, 1/2] xcos(pi*x
let u=x so that du=dx
and v=intgral cos (xpi)dx
v=(1/pi)sin(pi*x)
integration by parts
uv-itgral[0,1/2]vdu just plug ins
(1/pi)sinpi*x]-(1/pi)itgrlsin(pi*x)dx from 0 to 1/2
(1/pi)x sinpi*x - (1/pi)[-(1/pi) cos pi*x] from 0 to 1/2
=(1/2pi)+(1/pi^2)[cos pi*x/2-cos 0]
=1/2pi - 1/2pi^2
=(pi-2)/2pi^2 ans</span>
Answer:
B and C
Step-by-step explanation:
To figure out the average of all of the scores, you add all of the numbers together and then divide by how many numbers there are. The average shows about how well they did. Anne's friends average was 90 and was higher than Joan's friends average which was 75. Then the lowest score was definitely 78. So the answer would be B and C.
