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velikii [3]
3 years ago
6

Please help this is for a friend with co vid- 19

Mathematics
1 answer:
postnew [5]3 years ago
5 0

Answer:

am not sure but

Step-by-step explanation:

since they are similar they must have similar ratio

so 12/4 =3/1

so 3:1

4*3=12

for other sides I think

9*3 =27

and

6*3=18

y=27

x=18

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What is the answer for<br> -4x+4y=12<br> 3x-4y=-18
Liula [17]
Use elimination.

-x = -6
X = 6

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Y = 9

(X,y)

(6,9) is the solution
6 0
4 years ago
I’m confused on this one
kvv77 [185]
The answer is 42.

The question is asking for angle N. We know from the question that angle N is equal to angle E (Don't think about the scale factor because it only applies to the sides. They're just trying to trick you).

To find angle E:
79 + 6x + 11  + 7x - 14 = 180
Move numbers to the right side:
6x + 7x = 180 - 79 - 11 + 14
Combine like terms:
13x = 104
Divide both sides by 13:
x = 8
The formula for angle E:
7x - 14
Plug in the 8:
7 \times 8 - 14 = 56 - 14 = 42
The angle measure of E is 42. So angle N is automatically 42 too.

To solidify, we can try to use the formula which they give us for angle N:
3x + 18 = 24 + 18 = 42
8 0
3 years ago
A company paid $72 for 2 cases of printer paper each case contained 12 packages of paper next month the company's office manager
Tems11 [23]
To figure out the cost for 180 packages, you must first calculate how many packages they bought for $72. Since each case holds 12 packages, for $72, the company bought 24 packages (12×2). Then you have to divide 24 into 180 to figure out the cost for those 180 packages and get 7.5. To get the cost of the 180 packages, you must multiply 7.5 (the number of 24 packages that go into 180) by 72 (the cost of one group of 24 packages). You then get 540. The company must pay $540 for the 180 packages.
7 0
3 years ago
The product of (4z2 + 7z – 8) and (–z + 3) is –4z3 + xz2 + yz – 24.
jeka57 [31]
x is equal to 5 and y is equal to 29


9 0
3 years ago
Read 2 more answers
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Aleksandr-060686 [28]

Answer:

x=2

y=-3

Step-by-step explanation:

3 0
3 years ago
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