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3 years ago

15

The model below, the anchor of a guy-wire is 16 feet away from the telephone pole. John puts a 5 foot pole under the guy-wire pa

rallel to the telephone pole (see image below).
John knows the distance he put his pole from the anchor, which is labeled X. John says he can use similar triangles to calculate the height of where the guy-wire meets the telephon
ble.
o you agree with John's statement that he can prove similarity if we know side x? Provide mathematical justification.
h
5 ft
16 ft
В І у

1 answer:

beks73 [17]3 years ago

8 0

Answer:

Yes, because the two triangles share common segments.

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Please help!! WILL MARK BRAINLIEST

d1i1m1o1n [39]

Answer:

a= 2/5

b= 30

c= 18

d= 3:2

e= No, because the fraction or ratio is the same, all you need to do is simplify it!

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3 years ago

Ethan has 31 presents Alissa has 22 more than Ethan how many presents does Alissa have

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Alissa has 53 presents

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A rectangle. one side is 2x + 7 and the other is x+3

saveliy_v [14]

$\large{\green}\fcolorbox{purple}{pink}{\bf{\underline{\red{\color{red}Answer}}}}$

6x + 20

Step-by-step explanation:

<u>To</u><u> </u><u>find</u><u> </u><u>:</u><u>-</u>

Perimeter of rectangle

<u>Given</u><u> </u><u>:</u><u>-</u>

Length = 2x + 7

Breadth/width = x + 3

<u>Solution</u><u> </u><u>:</u><u>-</u>

<em>We</em><em> </em><em>know</em><em> </em><em>that</em>

<em> $\mathfrak {perimeter \: of \: rectangle =2(length + breadth) }$ </em>

<em>Now</em><em> </em><em>we</em><em> </em><em>will</em><em> </em><em>substitute</em><em> </em><em>the</em><em> </em><em>values</em><em> </em><em>of</em><em> </em><em>length</em><em> </em><em>and</em><em> </em><em>breadth</em>

<em> $\sf \longmapsto perimeter = 2 \{(2x + 7) + (x + 3) \} \\ \\ \\ \sf \longmapsto perimeter = 2 \{3x + 10 \} \\ \\ \\ \sf \longmapsto perimeter = 6x + 20$ </em>

6 0

1 year ago

Ali surveyed 200 students at a school and recorded the eye color and the gender of each student. of the 80 male students who wer

Aloiza [94]

Total number of students surveyed = 200
Number of male students = 80
Number of female students = 200 - 80 = 120

Number of brown eyed male students = 60
Probability of a brown eyed male student = 60 / 80 = 0.75.

Since, <span>eye color and gender are independent, this means that eye color is not affected by the gender. Thus, we expect a similar probability of brown eye for female as we had for male.

Let the number expected of brown eyed females be x, then x / 120 = 0.75.

Thus, x = 120(0.75) = 90.

Therefore, the number female students surveyed expected to be brown eyed is 90.</span>

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3 years ago

Find the area of quadrilateral ABCD. A. 27.28 units² B. 33.08 units² C. 28.53 units² D. 26.47 units²

Ludmilka [50]

Answer:

<h3> $\boxed{ \boxed{ \bold{ \purple{ \sf{28.53 \: {units}^{2} }}}}}$ </h3>

Option C is the correct option.

Step-by-step explanation:

For ABD

$\sf{ = \frac{2.89 + 8.59 + 8.6}{2} }$

$\sf{ = \frac{20.08}{2} }$

$\sf{ = 10.04}$

∆ ABD = $\sf{ = \sqrt{10.04(10.04 - 2.89)(10.04 - 8.59)(10.04 - 8.6)} }$

$\sf{ = \sqrt{10.04 \times 7.15 \times 1.45 \times 1.44 }}$

$\sf{ = \sqrt{149.8891} }$

$\sf{ = 12.2429}$

For ∆ ACD ,

$\sf{s = \frac{8.6 + 4.3 + 7.58}{2} }$

$\sf{ = \frac{20.48}{2} }$

$\sf{ = 10.24}$

∆ ACD = $\sf{ = \sqrt{10.24(10.24 - 8.6)(10.24 - 4.3)(10.24 - 7.58} }$

$\sf{ \sqrt{10.24 \times 1.64 \times 5.94 \times 2.66} }$

$\sf{ = \sqrt{265.3456} }$

$\sf{ = 16.2894}$

Area of quadrilateral ABCD = $\sf{12.2429 + 16.2894}$

$\sf{ = 28.5323}$

$\sf{ = 28.53}$ units ²

Hope I helped!

Best regards!

8 0

3 years ago