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3 years ago

Find the following arc measures for question 2

Mathematics

2 answers:

3241004551 [841]3 years ago

7 0

Answer:

arc BC = 16°

arc ABC = 196°

Step-by-step explanation:

arc BC = 180 - 164 = 16

arc ABC = 180 + 16 = 196

Debora [2.8K]3 years ago

7 0

MBC is 16. 360-180-164.
mABC is 196. 180+16

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Use the method of cylindrical shells to find the volume v generated by rotating the region bounded by the given curves about the

Oliga [24]

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3 years ago

How many radians are in 300 degrees?

Katena32 [7]

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3 years ago

Read 2 more answers

The point (-11,2) ____on the circle with radius 5 and center (-7,4)

nlexa [21]

Answer:

Does not lie

Step-by-step explanation:

The equation of the circle is

${(x + 7)}^{2} + {(y - 4)}^{2} = 25$

If we substitute x=-11, and y=2, we get that:

${( - 11 + 7)}^{2} + {(2 - 4)}^{2} = 25 \\ {4}^{2} + {2}^{2} = 25 \\ 20 = 25$

Which is false, meaning it does not lie on the circle

3 0

2 years ago

If eleven is added to the square of a number, the results is sixty. find all such numbers

Setler79 [48]

x^2 + 11 = 60 {11 is added to the square of a number to get 60}

x^2 = 49 {subtracted 11 from both sides}

x = 7 or -7 {took square root of both sides}

the numbers are 7 and -7

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3 years ago

Joshua traveled 5 hours from City A to City B. The distance between the cities is 260 miles. First he traveled at the constant s

ruslelena [56]

Joshua travelled for 3 hours at the constant speed of 60 mi/h

<h3>Solution:</h3>

Given that, Joshua traveled 5 hours from City A to City B

The distance between the cities is 260 miles.

First he traveled at the constant speed of 40 mi/h, and then at the constant speed of 60 mi/h.

So, let the number of hours he travelled with 40 mi/h be "n" hours and the distance travelled be "x" miles

Then, the time in which he travelled with 60 mi/h will be 5 – n hours and distance travelled will be 260 – x miles

We have to find how many hours did he travel at the constant speed of 60 mi/h

The relation between speed and distance is given as:

$\text { distance }=\text { speed } \times \text { time. }$

$\begin{array}{l}{40 \mathrm{mil} / \mathrm{h} \times \mathrm{n} \text { hours }= x \text { miles }} \\\\ {\rightarrow x=40 \mathrm{n} \rightarrow(1)} \\\\ {\text { And } 60 \times(5-\mathrm{n})=260-x \text { miles }}\end{array}$

$\begin{array}{l}{\rightarrow 300-60 n=260-40 n(\text { from }(1))} \\\\ {\rightarrow 60 n-40 n=300-260} \\\\ {\rightarrow 20 n=40} \\\\ {\rightarrow n=2}\end{array}$

So, he travelled 2 hours with speed of 40 mi/h and 5 – 2 = 3 hours with speed of 60 mi/h

Hence, he travelled for 3 hours

5 0

3 years ago