Answer:
6.33:20
Step-by-step explanation:
Answer:
(a)2(89x+84)
(b)![2(89x+84-x^2\pi)](https://tex.z-dn.net/?f=2%2889x%2B84-x%5E2%5Cpi%29)
Step-by-step explanation:
The dimensions of the larger rectangular field are:
- Length=5x + 12; Width
= 9x + 14.
The dimensions of the smaller rectangular soccer field are:
(a)Area of the part of the field that is outside the soccer field
=Area of the larger rectangular field - Area of the Soccer Field
=(5x+12)(9x+14)-5x(9x)
=(5x)(9x)+70x+108x+168-5x(9x)
=178x+168
=2(89x+84)
(b)Radius of the Semicircular Fountain =2x
From Part (a),
Area of the larger rectangular field - Area of the Soccer Field=178x+168
Area of the Semicircular Fountain =![\dfrac{\pi r^2}{2} =\dfrac{\pi (2x)^2}{2} =\dfrac{4x^2\pi}{2} =2x^2\pi](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cpi%20r%5E2%7D%7B2%7D%20%3D%5Cdfrac%7B%5Cpi%20%282x%29%5E2%7D%7B2%7D%20%3D%5Cdfrac%7B4x%5E2%5Cpi%7D%7B2%7D%20%3D2x%5E2%5Cpi)
Area of the Field that does not include the soccer field or the fountain.
=Area of the larger rectangular field - Area of the Soccer Field-Area of the Semicircular Fountain
![=178x+168-2x^2\pi\\=2(89x+84-x^2\pi)](https://tex.z-dn.net/?f=%3D178x%2B168-2x%5E2%5Cpi%5C%5C%3D2%2889x%2B84-x%5E2%5Cpi%29)
Answer:
I think the answer is 19
Step-by-step explanation:
Answer: 19 ≥ 3z + 1 ≥ - 5
Answer:
12 ft
Step-by-step explanation:
it's either 12 or 18, I have no idea :/