You can ise repeated reasonings
Your answer is: 2x^6-x^4+5x^3+2x^2+1\x^2
Answer:
36,000 possible codes.
Step-by-step explanation:
I guess you want the total number of arrangements possible.
The first digit can be any number from 0 to 8. the middle numbers must each be any number from 0 to 9 and the last digit must be 2,4,6 or 8.
So the number of arrangements possible = 9 * 10 * 10 * 10 * 4
= 36,000.
