Answer:
A substance containing only one type of atom or one type of molecule is a pure substance. Most of the matter around us, however, consists of mixtures of pure substances. Air, wood, rocks and dirt are examples of such mixtures. Mixtures can be further classified as Homogeneous and Heterogeneous.
Chemical properties of arsenic - Health effects of arsenic - Environmental effects of arsenic
Atomic number33Atomic mass74.9216 g.mol -1Electronegativity according to Pauling2.0Density5.7 g.cm-3 at 14°CMelting point814 °C (36 atm
Answer:
density=mass/volume
Explanation:
density is defined as mass per unit volume.
Explanation:
The given reaction will be as follows.
............. (1)
= ![[Ag^{+}][Cl^{-}] = 1.8 \times 10^{-10}](https://tex.z-dn.net/?f=%5BAg%5E%7B%2B%7D%5D%5BCl%5E%7B-%7D%5D%20%3D%201.8%20%5Ctimes%2010%5E%7B-10%7D)
Reaction for the complex formation is as follows.
........... (2)
= ![\frac{[Ag(NH_{3})_{2}]}{[Ag^{+}][NH_{3}]^{2}} = 1.0 \times 10^{8}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BAg%28NH_%7B3%7D%29_%7B2%7D%5D%7D%7B%5BAg%5E%7B%2B%7D%5D%5BNH_%7B3%7D%5D%5E%7B2%7D%7D%20%3D%201.0%20%5Ctimes%2010%5E%7B8%7D)
When we add both equations (1) and (2) then the resultant equation is as follows.
............. (3)
Therefore, equilibrium constant will be as follows.
K = 
= 
= 
Since, we need 0.010 mol of AgCl to be soluble in 1 liter of solution after after addition of
for complexation. This means we have to set
=
= 
= 0.010 M
For the net reaction, ![AgCl(s) + 2NH_{3}(aq) \rightarrow [Ag(NH_{3})_{2}]^{+}(aq) + Cl^{-}(aq)](https://tex.z-dn.net/?f=AgCl%28s%29%20%2B%202NH_%7B3%7D%28aq%29%20%5Crightarrow%20%5BAg%28NH_%7B3%7D%29_%7B2%7D%5D%5E%7B%2B%7D%28aq%29%20%2B%20Cl%5E%7B-%7D%28aq%29)
Initial : 0.010 x 0 0
Change : -0.010 -0.020 +0.010 +0.010
Equilibrium : 0 x - 0.020 0.010 0.010
Hence, the equilibrium constant expression for this is as follows.
K = ![\frac{[Ag(NH_{3})^{+}_{2}][Cl^{-}]}{[NH_{3}]^{2}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BAg%28NH_%7B3%7D%29%5E%7B%2B%7D_%7B2%7D%5D%5BCl%5E%7B-%7D%5D%7D%7B%5BNH_%7B3%7D%5D%5E%7B2%7D%7D)
= 
x = 0.0945 mol
or, x = 0.095 mol (approx)
Thus, we can conclude that the number of moles of
needed to be added is 0.095 mol.
Answer:
Explanation:
we know that number of moles=mass(in grams)/molar mass
for the mass of oxygen the equation becomes
mass=number of moles*molar mass