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jok3333 [9.3K]
2 years ago
14

Consider the balanced equation.

Chemistry
1 answer:
viktelen [127]2 years ago
8 0
28.4% is the answer and that is ur answer
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Please help!! A lot of points!!
Artist 52 [7]
Mean: the average. you have to add the values of the numbers and then divide by the amount of numbers there are. a common mistake to avoid is forgetting to divide the numbers at the end or subtracting them instead of adding.

mean: the middle number. you would first need to order the numbers from least to greatest. a common mistake to avoid is finding the middle number before ordering it from least to greatest

these two can also be commonly mistaken for one another because of the similar spelling.
7 0
3 years ago
15g of FeCI3 is dissolved in 450 mL of solution. What is the concentration of [CI-]?
storchak [24]

The concentration of [CI-] : 0.617 M

<h3>Further explanation</h3>

FeCl₃ dissolved in 450 mL of solution(will dissociate )

Reaction

FeCl₃⇒Fe³⁺+3Cl⁻

  • mol FeCl₃(MW=162,2 g/mol)

\tt \dfrac{15}{162.2}=0.0925

  • mol Cl⁻ :

\tt \dfrac{3}{1}\times 0.0925=0.2775

  • molarity of Cl⁻ :

\tt \dfrac{0.2775}{0.45}=0.617~M

7 0
2 years ago
A gold coin contains 3.47 × 10^23<br> gold atoms.<br> What is the mass of the coin in grams?
VashaNatasha [74]

Answer:

Mass = 114.26 g

Explanation:

Given data:

Number of gold atoms = 3.47×10²³ atoms

Mass in gram = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

3.47×10²³ atoms × 1 mol  /6.022 × 10²³ atoms

0.58 mol

Mass of gold:

Mass = number of moles × molar mass

Mass = 0.58 mol × 197 g/mol

Mass = 114.26 g

4 0
3 years ago
Determine the oxidation number of sodium in Na202
Olegator [25]

Answer:

+1

Explanation:

Na₂O₂

NOTE: the oxidation number of oxygen is always –2 except in peroxides where it is –1.

Thus, we can obtain the oxidation number of sodium (Na) in Na₂O₂ as illustrated below:

Na₂O₂ = 0 (oxidation number of ground state compound is zero)

2Na + 2O = 0

O = –1

2Na + 2(–1) = 0

2Na – 2 = 0

Collect like terms

2Na = 0 + 2

2Na = 2

Divide both side by 2

Na = 2/2

Na = +1

Thus, the oxidation number of sodium (Na) in Na₂O₂ is +1

5 0
2 years ago
Which factors affect electronegativity?
nasty-shy [4]
I believe d is the correct answer
3 0
3 years ago
Read 2 more answers
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